Codeforces Global Round 13 |
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Finished |
Let $$$F_k$$$ denote the $$$k$$$-th term of Fibonacci sequence, defined as below:
You are given a tree with $$$n$$$ vertices. Recall that a tree is a connected undirected graph without cycles.
We call a tree a Fib-tree, if its number of vertices equals $$$F_k$$$ for some $$$k$$$, and at least one of the following conditions holds:
Determine whether the given tree is a Fib-tree or not.
The first line of the input contains a single integer $$$n$$$ ($$$1 \leq n \leq 2 \cdot 10^5$$$) — the number of vertices in the tree.
Then $$$n-1$$$ lines follow, each of which contains two integers $$$u$$$ and $$$v$$$ ($$$1\leq u,v \leq n$$$, $$$u \neq v$$$), representing an edge between vertices $$$u$$$ and $$$v$$$. It's guaranteed that given edges form a tree.
Print "YES" if the given tree is a Fib-tree, or "NO" otherwise.
You can print your answer in any case. For example, if the answer is "YES", then the output "Yes" or "yeS" will also be considered as correct answer.
3 1 2 2 3
YES
5 1 2 1 3 1 4 1 5
NO
5 1 3 1 2 4 5 3 4
YES
In the first sample, we can cut the edge $$$(1, 2)$$$, and the tree will be split into $$$2$$$ trees of sizes $$$1$$$ and $$$2$$$ correspondently. Any tree of size $$$2$$$ is a Fib-tree, as it can be split into $$$2$$$ trees of size $$$1$$$.
In the second sample, no matter what edge we cut, the tree will be split into $$$2$$$ trees of sizes $$$1$$$ and $$$4$$$. As $$$4$$$ isn't $$$F_k$$$ for any $$$k$$$, it's not Fib-tree.
In the third sample, here is one possible order of cutting the edges so that all the trees in the process are Fib-trees: $$$(1, 3), (1, 2), (4, 5), (3, 4)$$$.
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