Codeforces Round 748 (Div. 3) |
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Finished |
It is given a non-negative integer $$$x$$$, the decimal representation of which contains $$$n$$$ digits. You need to color each its digit in red or black, so that the number formed by the red digits is divisible by $$$A$$$, and the number formed by the black digits is divisible by $$$B$$$.
At least one digit must be colored in each of two colors. Consider, the count of digits colored in red is $$$r$$$ and the count of digits colored in black is $$$b$$$. Among all possible colorings of the given number $$$x$$$, you need to output any such that the value of $$$|r - b|$$$ is the minimum possible.
Note that the number $$$x$$$ and the numbers formed by digits of each color, may contain leading zeros.
The figure above shows an example of painting the number $$$x = 02165$$$ of $$$n = 5$$$ digits for $$$A = 3$$$ and $$$B = 13$$$. The red digits form the number $$$015$$$, which is divisible by $$$3$$$, and the black ones — $$$26$$$, which is divisible by $$$13$$$. Note that the absolute value of the difference between the counts of red and black digits is $$$1$$$, it is impossible to achieve a smaller value.
The first line contains one integer $$$t$$$ ($$$1 \le t \le 10$$$) — the number of test cases. Then $$$t$$$ test cases follow.
Each test case consists of two lines. The first line contains three integers $$$n$$$, $$$A$$$, $$$B$$$ ($$$2 \le n \le 40$$$, $$$1 \le A, B \le 40$$$). The second line contains a non-negative integer $$$x$$$ containing exactly $$$n$$$ digits and probably containing leading zeroes.
For each test case, output in a separate line:
The number formed by digits colored red should divisible by $$$A$$$. The number formed by digits colored black should divisible by $$$B$$$. The value $$$|r-b|$$$ should be minimal, where $$$r$$$ is the count of red digits, $$$b$$$ is the count of black digits. If there are many possible answers, print any of them.
4 5 3 13 02165 4 2 1 1357 8 1 1 12345678 2 7 9 90
RBRBR -1 BBRRRRBB BR
The first test case is considered in the statement.
In the second test case, there are no even digits, so it is impossible to form a number from its digits that is divisible by $$$2$$$.
In the third test case, each coloring containing at least one red and one black digit is possible, so you can color $$$4$$$ digits in red and $$$4$$$ in black ($$$|4 - 4| = 0$$$, it is impossible to improve the result).
In the fourth test case, there is a single desired coloring.
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