Codeforces Round 872 (Div. 1) |
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Finished |
There are $$$n$$$ people taking part in a show about VOCALOID. They will sit in the row of seats, numbered $$$1$$$ to $$$m$$$ from left to right.
The $$$n$$$ people come and sit in order. Each person occupies a seat in one of three ways:
Now you want to know what is the maximum number of people that can take a seat, if you can let people into the show in any order?
Each test consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. The description of test cases follows.
The first line of each test case contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n, m \le 10^5$$$) — the number of people and the number of seats.
The second line of each test case contains $$$n$$$ integers $$$x_1, x_2, \ldots, x_n$$$ ($$$-2 \le x_i \le m$$$, $$$x_i \ne 0$$$), the $$$i$$$-th of which describes the way in which the $$$i$$$-th person occupies a seat:
It is guaranteed that sum of $$$n$$$ and the sum of $$$m$$$ over all test cases don't exceed $$$10^5$$$.
For each test case output a single integer — the maximum number of people who can occupy a seat.
103 105 5 54 61 -2 -2 15 7-1 -1 4 -2 -26 75 -2 -2 -2 -2 -26 6-1 1 4 5 -1 46 8-1 -1 -1 3 -1 -26 75 -1 -2 -2 -2 -23 1-2 -2 12 55 -21 2-1
1 3 5 6 5 5 5 1 2 1
In the first test case, all the people want to occupy the $$$5$$$ seat, so only $$$1$$$ people can occupy the seat.
In the second test case, we can let people in order $$$1, 2, 3, 4$$$, then all but the last person can take a seat.
In the third test case, we can let people into the show in that order:
Let the third person in:
– | – | – | 3 | – | – | – |
Let the fourth person in:
– | – | – | 3 | 4 | – | – |
Let the fifth person in:
– | – | – | 3 | 4 | 5 | – |
Let the first person in:
– | – | 1 | 3 | 4 | 5 | – |
Let the second person in:
– | 2 | 1 | 3 | 4 | 5 | – |
Thus, all $$$5$$$ people took seats.
In the fifth test case, we can let people into the show in this order:
Let the fourth person in:
– | – | – | – | 4 | – |
Let the third person in:
– | – | – | 3 | 4 | – |
Let the sixth person in, he'll leave the show because he takes the third seat the third way and has to sit in the $$$4$$$ seat, but it's already taken:
– | – | – | 3 | 4 | – |
Let the fifth person in:
– | – | 5 | 3 | 4 | – |
Let the first person in:
– | 1 | 5 | 3 | 4 | – |
Let the second person in:
2 | 1 | 5 | 3 | 4 | – |
Thus, $$$5$$$ of people took seats.
In the seventh test case, we can let people into the show in this order:
Let the third person in:
3 | – | – | – | – | – | – |
Let the fourth person in:
3 | 4 | – | – | – | – | – |
Let the fifth person in:
3 | 4 | 5 | – | – | – | – |
Let the sixth person in:
3 | 4 | 5 | 6 | – | – | – |
Let the first person in:
3 | 4 | 5 | 6 | 1 | – | – |
Let the second person in, he will leave the show because he occupies the first way, but the $$$1$$$ seat is taken:
3 | 4 | 5 | 6 | 1 | – | – |
Thus, $$$5$$$ people took seats.
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