Let's define $$$f(S)$$$. Let $$$S$$$ be a multiset (i.e., it can contain repeated elements) of non-negative integers. In one operation, you can choose any non-empty subset of $$$S$$$ (which can also contain repeated elements), remove this subset (all elements in it) from $$$S$$$, and add the MEX of the removed subset to $$$S$$$. You can perform any number of such operations. After all the operations, $$$S$$$ should contain exactly $$$1$$$ number. $$$f(S)$$$ is the largest number that could remain in $$$S$$$ after any sequence of operations.
You are given an array of non-negative integers $$$a$$$ of length $$$n$$$. For each of its $$$n$$$ prefixes, calculate $$$f(S)$$$ if $$$S$$$ is the corresponding prefix (for the $$$i$$$-th prefix, $$$S$$$ consists of the first $$$i$$$ elements of array $$$a$$$).
The MEX (minimum excluded) of an array is the smallest non-negative integer that does not belong to the array. For instance:
The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 10^4$$$) — the number of test cases. Then follows the description of the test cases.
The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 2 \cdot 10^5$$$) — the size of array $$$a$$$.
The second line of each test case contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$0 \leq a_i \leq 2 \cdot 10^5$$$) — the array $$$a$$$.
It is guaranteed that the sum of all $$$n$$$ values across all test cases does not exceed $$$2 \cdot 10^5$$$.
For each test case, output $$$n$$$ numbers: $$$f(S)$$$ for each of the $$$n$$$ prefixes of array $$$a$$$.
48179 57 2 0 2 3 2 31031 0 381 0 1 2 4 3 0 2
179 2 3 3 3 4 4 5 1 1 2 2 1 2 2 3 3 5 5 5
Consider the first test case. For a prefix of length $$$1$$$, the initial multiset is $$$\{179\}$$$. If we do nothing, we get $$$179$$$.
For a prefix of length $$$2$$$, the initial multiset is $$$\{57, 179\}$$$. Using the following sequence of operations, we can obtain $$$2$$$.
Consider the second test case. For a prefix of length $$$1$$$, the initial multiset is $$$\{0\}$$$. If we apply the operation to $$$\{0\}$$$, the multiset becomes $$$\{1\}$$$. This is the answer.
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