Codeforces Round 900 (Div. 3) |
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Finished |
Aca and Milovan, two fellow competitive programmers, decided to give Vasilije a problem to test his skills.
Vasilije is given three positive integers: $$$n$$$, $$$k$$$, and $$$x$$$, and he has to determine if he can choose $$$k$$$ distinct integers between $$$1$$$ and $$$n$$$, such that their sum is equal to $$$x$$$.
Since Vasilije is now in the weirdest city in Serbia where Aca and Milovan live, Cacak, the problem seems weird to him. So he needs your help with this problem.
The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases.
The only line of each test case contains three integers $$$n$$$, $$$k$$$ and $$$x$$$ ($$$1 \le n \le 2 \cdot 10^5$$$, $$$1 \le k \le n$$$, $$$1 \le x \le 4 \cdot 10^{10}$$$) — the maximum element he can choose, the number of elements he can choose and the sum he has to reach.
Note that the sum of $$$n$$$ over all test cases may exceed $$$2 \cdot 10^5$$$.
For each test case output one line: "YES", if it is possible to choose $$$k$$$ distinct integers between $$$1$$$ and $$$n$$$, such that their sum is equal to $$$x$$$, and "NO", if it isn't.
You can output the answer in any case (for example, the strings "yEs", "yes", "Yes", and "YES" will be recognized as a positive answer).
125 3 105 3 310 10 556 5 202 1 26187856 87856 2609202300200000 190000 1900000000028 5 20042 2 20069 6 4047202 32455 613407217185977 145541 15770805980
YES NO YES YES NO NO YES NO NO NO YES YES
In the first test case $$$n = 5,\ k=3,\ x=10$$$, so we can choose the numbers: $$$2$$$, $$$3$$$, $$$5$$$, whose sum is $$$10$$$, so the answer is "YES".
In the second test case $$$n = 5, \ k=3, \ x=3$$$, there is no three numbers which satisfies the condition, so the answer is "NO". It can be shown that there are no three numbers whose sum is $$$3$$$.
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