I'm having some difficulties with this problems? Can you help me?
I think it can be solved by using Dynamic programming on tree, isn't it?
# | User | Rating |
---|---|---|
1 | jiangly | 3898 |
2 | tourist | 3840 |
3 | orzdevinwang | 3706 |
4 | ksun48 | 3691 |
5 | jqdai0815 | 3682 |
6 | ecnerwala | 3525 |
7 | gamegame | 3477 |
8 | Benq | 3468 |
9 | Ormlis | 3381 |
10 | maroonrk | 3379 |
# | User | Contrib. |
---|---|---|
1 | cry | 168 |
2 | -is-this-fft- | 165 |
3 | Dominater069 | 161 |
4 | atcoder_official | 160 |
5 | Um_nik | 159 |
6 | djm03178 | 157 |
7 | adamant | 153 |
8 | luogu_official | 151 |
9 | awoo | 149 |
10 | TheScrasse | 146 |
I'm having some difficulties with this problems? Can you help me?
I think it can be solved by using Dynamic programming on tree, isn't it?
We have an array of integer a[1], a[2], ... , a[N] and a number M.
We take a version of selection sort like this:
for i := 1 to M do
for j := i + 1 to N do
if (a[i] > a[j]) then swap(a[i], a[j])
After the program end, count the number of swap operator in it.
Limitation:
1 <= M <= N <= 105
abs(ai) <= 109
Example:
Input:
4 2
3 2 -1 -4
Output:
5
Explain:
After first loop of j: -4 3 2 -1
After second loop of j: -4 -1 3 2
So the number of swap operator is 5.
Name |
---|