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Автор 244mhq, история, 3 года назад, По-английски

We invite you to participate in CodeChef’s April Cook-Off, this Saturday, 2nd April, rated for all.

Time: 8:00 PM — 10:30 PM IST

California headquartered Customer Engagement Platform MoEngage is on board to hire candidates from the Chef's pool.

Who can apply?

Anyone who has Strong coding skills and 0-4 years of experience can apply.

Where is the application form?

Visit the April Cook-Off contest page to check the JD & application form.

Joining me on the problem setting panel are:

Prizes:

Also, announcing Scholarship for CodeChef Certification in Data Structure & Algorithms — More than 100 Indian participants in Divisions 1, 2, and 3 will win scholarships for the CodeChef Certification exam (discounted prices). Scholarship criteria can be found in the respective contest pages.

The video editorials of the problems will be available on our YouTube channel as soon as the contest ends. Subscribe to get notifications about our new editorials.

Also, if you have some original and engaging problem ideas, and you’re interested in them being used in CodeChef's contests, you can share them here.

Hope to see you participating. Good Luck!

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3 года назад, # |
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Auto comment: topic has been updated by 244mhq (previous revision, new revision, compare).

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3 года назад, # |
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Have the cash prizes for Global/Indian winners been discontinued?

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3 года назад, # |
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When i click on the Sorted Distances problem editorial it says "Oops! That page doesn’t exist or is private."..

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3 года назад, # |
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244mhq I noticed that my rating delta for Cook-Off coincides with the fake delta for Starters (there was an issue that temporarily made Starters 30 rated for Div. 1), so I suspect it may be wrong. Please investigate.

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3 года назад, # |
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All editorials are still not out. How to solve Chef Goes Shopping ?

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3 года назад, # |
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Xellos and foxy007, why haven't editorials for any of the Div-1 problems been released yet ?. It's highly unprofessional to not release the editorials even after 2 days of the contest. CodeChef_admin kindly look into this.

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    3 года назад, # ^ |
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    Sorry, it's my fault, I got delayed. (It'd be unprofessional to completely ignore my actual job instead.)

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      3 года назад, # ^ |
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      Sure. (I don't understand why would you even opt for this job if you had other stuff to take care of, just let someone else who has time do it. I mean it's not like you're doing this for free anyways)

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3 года назад, # |
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Since nobody talks about or solved XORDEGREE (and the editorial is yet to be out), I'll share my solution. My approach is to make the sum of degrees $$$2N$$$ or $$$2N-2$$$. The main observation is that, if the sum is larger than $$$2N$$$, we can reduce the sum by $$$2$$$ or $$$4$$$ without changing the XOR. However, it turned out that there are a few nasty edge cases, and it took me a lot of time to handle all of them. I don't know if it's the intended solution, and I'd like to hear a cleaner one if it exists.