char c = '"';
// it is compiled and successed.
I have a question that: why we can char c = '"';
instead of using char c = '\"'
.
I used to think that char c = '"'
is wrong before.
Thank you alot
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3839 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3612 |
7 | Geothermal | 3569 |
7 | cnnfls_csy | 3569 |
9 | ecnerwala | 3494 |
10 | Um_nik | 3396 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | Um_nik | 164 |
2 | maomao90 | 160 |
3 | -is-this-fft- | 159 |
4 | atcoder_official | 158 |
4 | cry | 158 |
4 | awoo | 158 |
7 | adamant | 155 |
8 | nor | 154 |
9 | TheScrasse | 153 |
10 | maroonrk | 152 |
char c = '"';
// it is compiled and successed.
I have a question that: why we can char c = '"';
instead of using char c = '\"'
.
I used to think that char c = '"'
is wrong before.
Thank you alot
Название |
---|
Because standard says so. And it always was that way.
https://www.open-std.org/jtc1/sc22/wg21/docs/papers/2017/n4713.pdf (Section 5.3.13)
We don't need to escape the character
"
when we put it between'
. The reason is just the compiler will understand it and there is no need for\
.But when we put it between
"
we need to escape it because if we don't it will be marked as the end of the string.