№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
5 | jqdai0815 | 3620 |
6 | Benq | 3564 |
7 | Kevin114514 | 3443 |
8 | ksun48 | 3434 |
9 | Rewinding | 3397 |
10 | Um_nik | 3396 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
10 | nor | 152 |
Название |
---|
You forgot about memoization in dfs.
The whole point of using reference variable is memoisation itself
Sorry, idk what is this. Im not c++ guru :( My thought is that linking and unlinking variable is time consuming and not O(1).Because you first allocate space in the heap and create a connection, then cut it off, which gives additional costs both in memory and time. So its causing tle.
Source ?
I only have link to Russian c# video. I think you dont need it. Its just base knowledge about struct, collections,heap,stack and how reference and pointers work.
Auto comment: topic has been updated by sojabhai (previous revision, new revision, compare).
I think it's the fact that $$$dp[x][lastSeen]$$$ is accessed multiple times in the TLE code (even if it's via a reference variable), and it's probably not cache optimised. Replacing the reference variable with just $$$dp[x][lastSeen]$$$ gives the same TLE result — 271896757
Makes sense , Thanks
Auto comment: topic has been updated by sojabhai (previous revision, new revision, compare).