Heyo Codefoworcers!

As a testuwuer I can confirm this contest has W rizz and you will get ratioed.

As a tester,

- .... .. ... -.-. --- -. - . ... - .. ... .- -.. .. ...- ....- .. -. -.. . . -..

i wanna be a testuwuer one day uwu

As a testuwuer, I must say the problems are uWu

as a tester, Dominater orz

Noice! cry round!

As a participant, I want to solve max questions

As a tester, I like chipotle.

cry is the best! cry cry cry :)

Div-4 is my only hope for AK :) Good luck to all!

best thing in month

maythisjourneyleadsusstardownard

what does this even mean

Decoded message for the binary pattern at the end.

I wish you all good luck for div 4.

Three subtasks is crazy !

As a tester, I confirm the problems are as good as cry

go learn unicode

I hope to reach Expert after this round!

One genuine question to cry, from where do you get such good emojis ?

gsrixiw mw hmz4 mrhihi OWO

May this journey lead us starward.

what do u mean, lol?

As a testuwuer, I must say the problems are uWu

May this journey lead us starward!

Yay! Div 4 Round

What is this message at end?

Hope to get 1300+ rating

best thing for me after dropping 216 rating in 4 contests and went back to pupil

am i the only one who did this?

int main(){
    string s;
    int g;
    while(1){
        cin>>s;
        g=0;
        for(char x:s){
            g=g*2;
            if(x=='1')g++;
        }
        cout<<char('a'+g);
    } 
}

maythisjourneyleadusstarward

@cry fan here :) hoping to do well and excited for it!!!

One task in three subtasks? omg, I had never seen that before! I hope the contest would be amazing, gl&hf

dcode.fr my beloved

May as well join in on the brainrot fun!

As a uwuriter, I hope you do well and UwU the OwO out of this round :)

Good emoji.

The binary code at end : May this journey lead us starward.

Another cry contest? Do we remember this Div 2 C with bad score distribution? https://codeforces.net/contest/1998 Or this Div 3 D "counting is fun"? https://codeforces.net/contest/1996

For Div 4 guys out there, be careful. Assume it's speedforces, cry doesn't like creating solvable for your level problems.

Please don't do cheating everyone. This discourage us.

hmm, that's interesting

I am a skibbidi testewer

like to get luck!

I am so excited about this div 4 Contest But, how come the Div 3 Round from yesterday not make me newbie I am still unrated And I solved a problem in it too

may this journey lead us starward

"May this journey lead us starward." The binary code at last.

MAY THIS JOURNEY LEAD US STARWARD

Cry Always make me Cry :(

Good luck everyone uwu

I remember last time there way a monkey and you have made us cry on problem C, what is your plans now [fearful emoji]?

is my cutie cutie cowontests ready yewet?

where is sum ??

vgoofficial damn man that Display Picture hits hard :)

cry oworz

About 5 years ago ratings used to start from 1500. In my first contest I solved one problem and my rating got reduced to 1430 something. "do not have a point of 1400 or higher in the rating", I have not been able to touch 1400 since then, am I not considered a trusted participant?

Please make it easy i wanna be a specialist

I hope to get at least 5

Hopefully no gpt solves

If I became a specialist in last round and registered before will I be rated or not for this contest ........Cause when I checked the participant list I was not marked as unrated as *user_name is the sign for unrated participant

been waiting for div 4. i am new here i try div 2 solved one question and after that no a single question i am able to make. Hope this one goes well.

The Binary Code

As a non-rated contestant, this is my first unrated round.

Cry is a rizzmaxxer this conetst got W rizz but me no attend so L Rizz (erm what the sigma).

oh skibidi round)

first time to unrate, wish to solve 6 problem

aiming for 0 solved

uwu

hope to become specialist in this contest

First unrated contest (⁠^⁠^⁠)

Got busted in the last Div3 and now again rated for DIV4, expecting to reach cyan again.

As a participant, orz BonTapHoa , nguyenkhangninh99 , lalid , huanjua , chikien2009 , Soab , Jackduy

Can someone help mere here in these question of recursion i am getting error "Time limit exceeded on test 2" my code " ~~~~~

#include <stdio.h>

void tobinary(int n) { 
    if (n > 1) {
        tobinary(n / 2);
    }
    printf("%d", n % 2);
}

int main() {
    int times;
    scanf("%d", &times);
    
    while (times--) {
        int decimal;
        scanf("%d", &decimal);
        
        if (decimal == 0) {
            printf("0");
        } else {
            tobinary(decimal);
        }
        
        printf("\n");
    }

    return 0;
}

~~~~~ " I am not understanding why its happening. PLease help i tried ChatGPT already but his solutions are not satisfying or capping the input

where is your bro "Sum" as cry and sum :) ?

How to participate in the contest?

I think it will be a great round!

01100 00000 11000 10011 00111 01000 10010 01001 01110 10100 10001 01101 00100 11000 01011 00100 00000 00011 10100 10010 10010 10011 00000 10001 10110 00000 10001 00011

If we map 00000 with 'a' and 00001 with 'b' and so on

It translates to : may this journey lead us starward

Only div 4 can save my ratings now ; learning and givng contests is surely good but it costs rating too without practising

I'll ak in 20 minutes.

Hoping to solve 5 questions in this round!

All the best Prateek077

Don't be upset bro. This contest just not for you.[problem:E= 111,122,133,000]

"MAY THIS JOURNEY LEAD US STARWARD"

Had to use chatgpt, lmao.

do not unrate plsssssss

Div 4 contest after a month and it became unrated

give more time and do it rated pls

went unrated (insert crying emoji)

So wonderful round! I was top 2000, but it became unrated :(

Solved a problem in 1.5 mins for the first time in my damn life, and they made it unrated :(

Div.4 always suffer from poor performance? not the first time to occur that! so why to be unratted? An unsuccessful decision

What, unrated, well, (∩︵∩) bye, gonna search my waifu!

POV:

WHAT THE HECK IT IS UNRATED

Solved half the contest on m1.codeforces.com and gotta say, the minimalistic experience was quite refreshing :D

I hate PROBLEM C!

Such good round but got unrated! I was prepared to do my best and reach Specialist. But codeforces became queueforces and then website crashed.

it was supposed to be my combeck round ;( as i was about to solve F it become unrated even though if it didnt crash i would have done much better

Is this unrated?

Div 4 could be one of the only chances for noobs like me to get ratings improved.However,unrated.:( ......Hope for the next turn.

Codeforces server is Mike's phone.

Really wish it wasn't made unrated. Last div 3 contest went terrible, and I was hoping to give a comeback with this one. Bad luck :(

managed to solve 6 problems within 1.5 hrs for the first time!

was having the best performance of my career and then i heard "unrated" :(

very sad that the contest got unrated. Very fun questions

I could have gone back to specialist again if the contest was rated. This is just sad.

it was a cute round , i hope it was rated

I'm surprised I solved D under pressure. I'm usually bad at geometry

please rate this round 😭

I didn't find anything unusual, div3/4 has been always slow and lagging due to large number of participant.

why unrated this?

Making the round unrated just for the sake of "speedforces" just doesn't make sense to me tbh. What matters more is someone who solves more problems will place higher than someone who doesn't. Also the situation is the same for everybody, so it doesn't affect much to whoever has the ability to solve more problems.

who can tell me how to do E?

in G1, isn't the idea just find the longest consecutive subarray in the interval $$$ [l, r] $$$ and then answer for that query will be $$$ k - x $$$ where $$$ x $$$ is the length of longest increasing consecutive subarray. I was solving that with segment tree and some dp precalculation. Even my stress test couldn't find anything wrong.

auto brute = [&] (int l, int r) -> int{
    int ans = 1, cur = 1;
    for(int i = l + 1; i < r; i++){
        if(a[i] == a[i - 1] + 1) {
            // cout << "y" << "\n";
            cur++;
        }
        else{
            ans = max(ans, cur);
            cur = 1;
        }
    }
    ans = max(ans, cur);
    return ans;
};

Submission link