Given a number n as input how to find the (all the primitive roots of n) % n if n is prime. please give me some hint how can i calculate the primitive roots.. TIA.
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3831 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | gamegame | 3386 |
10 | ksun48 | 3373 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 164 |
1 | maomao90 | 164 |
3 | Um_nik | 163 |
4 | atcoder_official | 160 |
5 | -is-this-fft- | 158 |
6 | awoo | 157 |
7 | adamant | 156 |
8 | TheScrasse | 154 |
8 | nor | 154 |
10 | Dominater069 | 153 |
Название |
---|
in this spoj problem how can i find the (product all the primitive roots of n) % n without generating all the primitive roots of n ? any hint please...
For your question: sum of numbers relatively prime and less than N is Nφ(N) / 2. (Because if gcd(x, N) = 1 then gcd(N - x, N) = 1). But since for any primitive root g, gi is primitive root if and only if gcd(i, φ(N)) = 1. So their product will be gφ(φ (N)) * φ (N) / 2 which is ( - 1)φ(φ(n)) since g is primitive root. For you particular case it is -1.