I've been solving 1311C - Выполни комбо and when i used memset I received TLE 73574138 but when I changed to iterative method I received AC 73575826. This is not the first time happening. What the reason behind this?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3839 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3612 |
7 | Geothermal | 3569 |
8 | ecnerwala | 3494 |
9 | Um_nik | 3396 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | Um_nik | 164 |
2 | -is-this-fft- | 162 |
3 | maomao90 | 159 |
3 | atcoder_official | 159 |
5 | cry | 158 |
5 | awoo | 158 |
7 | adamant | 155 |
8 | nor | 154 |
9 | TheScrasse | 153 |
10 | Dominater069 | 152 |
I've been solving 1311C - Выполни комбо and when i used memset I received TLE 73574138 but when I changed to iterative method I received AC 73575826. This is not the first time happening. What the reason behind this?
Name |
---|
Every time you use memset with the third parameter $$$sizeof(a)$$$, it fills the whole array (or matrix) with corresponding values. But because the number of test cases in this problem can be up to $$$10^4$$$, you can fill up $$$10^4 \cdot 2 \cdot 10^5 \cdot 26 = 52 \cdot 10^9$$$ elements in the worst case. Despite the fact that memset is a very fast function, $$$52$$$ billion is a huge number of operations. But when you fill up all values iteratively, you can be sure that you will do this at most $$$\sum n \cdot 26$$$ times (i.e. $$$2 \cdot 10^5 \cdot 26 = 5.2 \cdot 10^6$$$ times.
Thank you, didn't think of that