Auto comment: topic has been updated by Jim_Moriarty_ (previous revision, new revision, compare).

Assume distinct words are on distinct lines. Do not consider one group as single string.

You can do it with string stream tokenizer by tokenizing the string according to any character. here's sample code for that, i tokenized the string by white space character ' '.

#include <bits/stdc++.h>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstring>
#include <chrono>
#include <complex>
#define int long long int
using namespace std;
int32_t main(){
    #ifndef ONLINE_JUDGE
        // for getting input from input.txt
        freopen("input.txt", "r", stdin);
        // for writing output to output.txt
        freopen("output.txt", "w", stdout);
    #endif
    int t=1;
    string s,tok;
    while(t--){
        getline(std::cin,s);
        stringstream tokenizer(s);
        while(getline(tokenizer,tok,' ')){
            // if(tok=="not"){

            //     f=1;
            //     break;
            // }
            cout << tok << endl;
        }
    }
}

Here's cakewalk problem for stream tokenizer

Hi, you can use getline function. Here is more information: getline (string) — C++ Reference

vector<string> list[2];
string s;
getline(cin, s); // 1st line
string word;
s += ' ';
for(int i = 0; i < s.size(); i++){
	if(s[i] == ' '){
		list[0].push_back(word);
		word.clear();
	}else word += s[i];
}
getline(cin, s); // waster line
getline(cin, s); // 2nd line
s += ' ';
for(int i = 0; i < s.size(); i++){
	if(s[i] == ' '){
		list[1].push_back(word);
		word.clear();
	}else word += s[i];
}