Next SRM will be held on Saturday, 20:00 MSK (12:00 EDT).
→ Pay attention
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | tourist | 3985 |
| 2 | jiangly | 3814 |
| 3 | jqdai0815 | 3682 |
| 4 | Benq | 3529 |
| 5 | orzdevinwang | 3526 |
| 6 | ksun48 | 3517 |
| 7 | Radewoosh | 3410 |
| 8 | hos.lyric | 3399 |
| 9 | ecnerwala | 3392 |
| 9 | Um_nik | 3392 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 170 |
| 2 | Um_nik | 162 |
| 3 | atcoder_official | 160 |
| 3 | maomao90 | 160 |
| 5 | djm03178 | 158 |
| 5 | -is-this-fft- | 158 |
| 7 | adamant | 154 |
| 7 | Dominater069 | 154 |
| 9 | awoo | 152 |
| 9 | luogu_official | 152 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Dec/28/2024 16:05:03 (i1).
Desktop version, switch to mobile version.
Supported by
Screencast
Could someone please explain to me Division 2, 500 ?
Waht I understood is that since they all move at the same speed, we can consider them to be still and we have to pick 2 positions where the total will be the maximum.
I am not sure however how I can pick those 2 positions. I was thinking to iterate over the tails but not sure if that would be optimal or why.
Editorial