We can solve the maximum (AND) subsequence of an array by checking the common bits in numbers in O(nlogn).But how can we find a susequence with maximum XOR?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3831 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | gamegame | 3386 |
10 | ksun48 | 3373 |
# | User | Contrib. |
---|---|---|
1 | cry | 164 |
1 | maomao90 | 164 |
3 | Um_nik | 163 |
4 | atcoder_official | 160 |
5 | -is-this-fft- | 158 |
6 | awoo | 157 |
7 | adamant | 156 |
8 | TheScrasse | 154 |
8 | nor | 154 |
10 | Dominater069 | 153 |
We can solve the maximum (AND) subsequence of an array by checking the common bits in numbers in O(nlogn).But how can we find a susequence with maximum XOR?
hello everyone,
Recently i came across this problem http://www.spoj.com/problems/DQUERY/en/. I coded the offline solution, but i was wondering how to solve it using persisent segment trees.I kept an array last_occur[i] which stores the latest occurence of the number i. now given a range (l,r) we need to find number of distinct elements with last_occur[i] < l.I got stuck here, how do we solve this part?
Name |
---|