Hi!
I've come across this piece of code of a (modified?) sieve and I'm trying to figure out what sieve[i]
means and how it works, specially the 2nd for.
Would you help me, please?
Thanks!
# | User | Rating |
---|---|---|
1 | tourist | 3985 |
2 | jiangly | 3814 |
3 | jqdai0815 | 3682 |
4 | Benq | 3529 |
5 | orzdevinwang | 3526 |
6 | ksun48 | 3517 |
7 | Radewoosh | 3410 |
8 | hos.lyric | 3399 |
9 | ecnerwala | 3392 |
9 | Um_nik | 3392 |
# | User | Contrib. |
---|---|---|
1 | cry | 169 |
2 | maomao90 | 162 |
2 | Um_nik | 162 |
4 | atcoder_official | 161 |
5 | djm03178 | 158 |
6 | -is-this-fft- | 157 |
7 | adamant | 155 |
8 | awoo | 154 |
8 | Dominater069 | 154 |
10 | luogu_official | 151 |
Hi!
I've come across this piece of code of a (modified?) sieve and I'm trying to figure out what sieve[i]
means and how it works, specially the 2nd for.
Would you help me, please?
Thanks!
I've come across this probability problem and could not solve it. In order to learn, I searched for the solution on the internet and found out that people just printed 1/2
. i.e., the answer, no matter the value of n
, is always 50%.
Why is that so? I tried making some DP for testing values under ~20 and only when n = 2 the answer is indeed 1/2
.
Can someone give me some help on this tough (for me) one?
Appreciate the help!
Name |
---|