Has anybody noticed that submission 222222222 is coming? I know it's not as news-breaking as 200000000, but nonetheless, a neat number! Let's hope the 2x9th submission is accepted 😎
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1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
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1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Has anybody noticed that submission 222222222 is coming? I know it's not as news-breaking as 200000000, but nonetheless, a neat number! Let's hope the 2x9th submission is accepted 😎
If you want a variable to be the negative of itself, do you use n = -n
, n *= -1
, or other methods? If so, suggest some methods down below.
I am trying to solve 165C using binary search, but it is getting TLE. Can anyone help?
Here's my code: 208389930
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
ll n, k;
ll pre[100005];
string s;
ll bs1(ll lo){
ll l = lo, r = n, mid;
while (l <= r){
mid = (l + r) / 2;
if (pre[mid] - pre[lo-1] <= k){
l = mid + 1;
} else {
r = mid - 1;
}
}
return r;
}
ll bs2(ll lo){
ll l = lo, r = n, mid;
while (l <= r){
mid = (l + r) / 2;
if (pre[mid] - pre[lo-1] >= k){
r = mid - 1;
} else {
l = mid + 1;
}
}
return l;
}
signed main(){
ll i, res;
cin >> k >> s;
n = s.size();
s = " " + s;
pre[0] = 0;
for (i = 1; i <= n; i++){
pre[i] = pre[i-1] + s[i] - '0';
}
res = 0;
for (i = 1; i <= n; i++){
res += bs1(i) - bs2(i) + 1;
}
cout << res;
}
Has anyone realized that Codeforces is reaching 200M submissions in the problem set? It will be a big day when this happens! Good luck getting the 200Mth submission! That person will go down in history!
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