Codeforces Round 821 (Div. 2) |
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Finished |
This is the easy version of the problem. In this version, $$$n \le 3000$$$, $$$x \ge y$$$ holds. You can make hacks only if both versions of the problem are solved.
You are given two binary strings $$$a$$$ and $$$b$$$, both of length $$$n$$$. You can do the following operation any number of times (possibly zero).
You have to find the minimum cost needed to make $$$a$$$ equal to $$$b$$$ or say there is no way to do so.
The first line contains one integer $$$t$$$ ($$$1 \le t \le 600$$$) — the number of test cases.
Each test case consists of three lines. The first line of each test case contains three integers $$$n$$$, $$$x$$$, and $$$y$$$ ($$$5 \le n \le 3000$$$, $$$1 \le y \le x \le 10^9$$$) — the length of the strings, and the costs per operation.
The second line of each test case contains the string $$$a$$$ of length $$$n$$$. The string only consists of digits $$$0$$$ and $$$1$$$.
The third line of each test case contains the string $$$b$$$ of length $$$n$$$. The string only consists of digits $$$0$$$ and $$$1$$$.
It is guaranteed that the sum of $$$n$$$ over all test cases doesn't exceed $$$3000$$$.
For each test case, if there is no way to make $$$a$$$ equal to $$$b$$$, print $$$-1$$$. Otherwise, print the minimum cost needed to make $$$a$$$ equal to $$$b$$$.
45 8 701001001015 7 201000110117 8 3011100101000015 10 10110001100
8 -1 6 0
In the first test case, selecting indices $$$2$$$ and $$$3$$$ costs $$$8$$$, which is the minimum possible cost.
In the second test case, we cannot make $$$a$$$ equal to $$$b$$$ using any number of operations.
In the third test case, we can perform the following operations:
The total cost is $$$6$$$.
In the fourth test case, we don't have to perform any operations.
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