int limit = 1 << n;
for (int i = 0; i < limit; i++) {
if (Integer.bitCount(i) >= 3) {
System.out.println(i);
}
}
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Faster way to generate these numbers?
int limit = 1 << n;
for (int i = 0; i < limit; i++) {
if (Integer.bitCount(i) >= 3) {
System.out.println(i);
}
}
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