Today, I was trying to solve 626E - Простая асимметрия, and I had some troubles implementing a ternary search on integers! I knew how to run a ternary search on doubles, but I didn't know how to do it on integers.

So after getting it accepted, I tried reading accepted codes of other people and I found a nice way to do it. since many of the best coders in codeforces (including tourist and Errichto) didn't use this while solving 626E - Простая асимметрия, I think many people don't know about it!

So here it is!

int lo = -1, hi = n;
while (hi — 1 > lo){
    int mid = (hi + lo)>>1;
    if (f(mid) < f(mid + 1)) 
         hi = mid;
    else 
         lo = mid; 
}
//lo + 1 is the answer