| # | User | Rating |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3823 |
| 3 | Benq | 3738 |
| 4 | Radewoosh | 3633 |
| 5 | jqdai0815 | 3620 |
| 6 | orzdevinwang | 3529 |
| 7 | ecnerwala | 3446 |
| 8 | Um_nik | 3396 |
| 9 | ksun48 | 3390 |
| 10 | gamegame | 3386 |
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 167 |
| 2 | maomao90 | 163 |
| 2 | Um_nik | 163 |
| 4 | atcoder_official | 161 |
| 5 | adamant | 159 |
| 6 | -is-this-fft- | 158 |
| 7 | awoo | 157 |
| 8 | TheScrasse | 154 |
| 9 | nor | 153 |
| 9 | Dominater069 | 153 |
Proof: given 2 nodes u and v, IF for each pair of paths between u and v there is a common in-between node, there is a GLOBAL common in-between node (a.k.a. articulation point) shared by all paths between u and v ??
Given 2 nodes u and v, IF for each pair of paths between u and v there is a common in-between node, THEN there is a GLOBAL common in-between node (a.k.a. articulation point) shared by all paths between u and v.
tl;dr does pairwise imply global?
Is this true? Any formal proofs?
| Rev. | Lang. | By | When | Δ | Comment | |
|---|---|---|---|---|---|---|
| en3 |
|
pabloskimg | 2018-04-29 04:15:56 | 5 | ||
| en2 |
|
pabloskimg | 2018-04-29 04:12:11 | 3 | ||
| en1 |
|
pabloskimg | 2018-04-29 04:11:24 | 526 | Initial revision (published) |
