Example : [4,2,2,2,2], k=8

Answer : — (1)

As only 1 quadruple(2+2+2+2=8) exists whose sum is '8' :-)

I know the brute-force O(n^4) algorithm , I even know an O(n^2.log(n)) algorithm , but it unfortunately does not work with duplicate elements :-(

Any better-efficient way to solve it ? :-)

Thanks!:-)