Hi codeforces↵
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Today i will talk about special case in Ternary search↵
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You know when we use Ternary search it's done on a **parabola** to find its peak↵
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This is a simple code to find the peak of a parabola where the peak is facing down :↵
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L = range_beginning, R = range_ending;↵
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while(R > L)↵
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{↵
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x = (L+R)/2; ↵
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if( f(x+1) < f(x) )↵
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L = x+1;↵
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else↵
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R = x;↵
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}↵
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But in this special case i need to find the peak of a parabola that has constant value in some ranges as shown on the photo below : ↵
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↵
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You notice that f(x) = f(x+1) therefor the code from above won't work correctly in this case.↵
↵
I need help to find a solution for that case.↵
↵
Today i will talk about special case in Ternary search↵
↵
You know when we use Ternary search it's done on a **parabola** to find its peak↵
↵
This is a simple code to find the peak of a parabola where the peak is facing down :↵
↵
L = range_beginning, R = range_ending;↵
↵
while(R > L)↵
↵
{↵
↵
x = (L+R)/2; ↵
↵
if( f(x+1) < f(x) )↵
↵
L = x+1;↵
↵
else↵
↵
R = x;↵
↵
}↵
↵
↵
↵
↵
You notice that f(x) = f(x+1) therefor the code from above won't work correctly in this case.↵
↵
I need help to find a solution for that case.↵