x is and Element of Array 1 and y is the element of array 2, Find the number of ways in the two arrays where x^y>y^x (NOTE: ^ denotes power here and not the XOR)

First line inputs the number of test cases, second line input the number of elements in two upcoming arrays third line inputs the first array fourth line inputs the second array

EXAMPLE: sampleINPUT:

1
3 2
2 1 6
1 5

sampleOUTPUT 3

<<HERE IS MY POOR CODE,JUST A BRUTE FORCE!!>> IS THERE ANY WAY TO SOLVE IT IN TIME LESS THAN THIS??

#include<bits/stdc++.h>
using namespace std;

int main()
{

    int t;
    cin>>t;
    while(t--)
    {
        int m,n;
        cin>>m>>n;
        vector<int> vm(m,0);
        vector<int> vn(n,0);
        for(auto &it:vm)
            cin>>it;
        for(auto &it:vn)
            cin>>it;
            int counts=0;
        for(int x:vm)
            for(int y:vn)
        {

            if(pow(x,y)>(pow(y,x)))
            {
                counts++;

            }
            continue;
        }
        cout<<counts<<endl;
    }
}