The first code is giving correct answer while second code is giving wrong answer. The only difference between these two codes is:<br>↵
In the first code the return value is -2*inf in the getmax function while it is -inf in the second code. Can anybody please help me figure out what is the problem?<br>↵
[Link to Problem](https://cses.fi/problemset/result/902905/)↵
↵
<spoiler summary="Code 1">↵
↵
~~~~~↵
#include<bits/stdc++.h>↵
using namespace std;↵
#define ll long long int↵
#define pii pair<ll,ll>↵
#define rep(i, begin, end) for (__typeof(end) i = (begin) - ((begin) > (end)); i != (end) - ((begin) > (end)); i += 1 - 2 * ((begin) > (end)))↵
#define vi vector<ll>↵
#define vii vector<pii>↵
#define all(x) x.begin(),x.end()↵
#define eb emplace_back↵
#define yes cout<<"YES"<<endl; return;↵
#define no cout<<"NO"<<endl; return;↵
#define flus fflush(stdin); fflush(stdout);↵
#define F first↵
#define S second↵
#define np next_permutation↵
#define inf 1e18↵
#define mod 1000000007↵
#define N 200100↵
#define pi (double)2*acos(0.0)↵
#define minpq priority_queue <ll, vector<ll>, greater<ll>>↵
#define maxpq priority_queue<ll> ↵
void sout(){↵
cout<<endl;↵
}↵
template <typename T,typename... Types>↵
void sout(T var1,Types... var2){↵
cout<<var1<<" ";↵
sout(var2...);↵
}↵
/*******************************************************************/↵
↵
↵
ll arr[N];↵
ll pre[N];↵
ll tree[4*N];↵
ll n,a,b;↵
void build(ll s,ll e,ll ind=1){↵
if(s==e){↵
tree[ind]=pre[s];↵
return;↵
}↵
ll mid=(s+e)/2;↵
build(s,mid,2*ind);↵
build(mid+1,e,2*ind+1);↵
tree[ind]=max(tree[2*ind],tree[2*ind+1]);↵
}↵
ll getmax(ll s,ll e,ll l,ll r,ll ind=1){↵
if(e<l or s>r)↵
return -2*inf;↵
if(s>=l and e<=r)↵
return tree[ind];↵
ll mid=(s+e)/2;↵
ll a=getmax(s,mid,l,r,2*ind);↵
ll b=getmax(mid+1,e,l,r,2*ind+1);↵
return max(a,b);↵
}↵
ll getmax(ll l,ll r){↵
return getmax(0,n,l,r);↵
}↵
void solve(){↵
↵
cin>>n>>a>>b;↵
↵
rep(i,1,n+1){↵
cin>>arr[i];↵
}↵
↵
pre[0]=0;↵
rep(i,1,n+1){↵
pre[i]=pre[i-1]+arr[i];↵
}↵
↵
build(0,n);↵
ll ans=-inf;↵
for(ll i=a;i<=n;i++){↵
ll x=getmax(min(n,i+1),min(n,i+b-a));↵
x=x-pre[i];↵
x=max(x,0LL);↵
// sout("x",x);↵
ll loc=x+pre[i]-pre[i-a];↵
ans=max(ans,loc);↵
}↵
cout<<ans<<endl;↵
}↵
↵
int main(){↵
ios_base::sync_with_stdio(false);↵
cin.tie(NULL);↵
int t;↵
// cin>>t;↵
t=1;↵
while(t--){↵
solve();↵
}↵
}↵
~~~~~↵
↵
↵
</spoiler>↵
↵
↵
<spoiler summary="Code 2">↵
↵
~~~~~↵
#include<bits/stdc++.h>↵
using namespace std;↵
#define ll long long int↵
#define pii pair<ll,ll>↵
#define rep(i, begin, end) for (__typeof(end) i = (begin) - ((begin) > (end)); i != (end) - ((begin) > (end)); i += 1 - 2 * ((begin) > (end)))↵
#define vi vector<ll>↵
#define vii vector<pii>↵
#define all(x) x.begin(),x.end()↵
#define eb emplace_back↵
#define yes cout<<"YES"<<endl; return;↵
#define no cout<<"NO"<<endl; return;↵
#define flus fflush(stdin); fflush(stdout);↵
#define F first↵
#define S second↵
#define np next_permutation↵
#define inf 1e18↵
#define mod 1000000007↵
#define N 200100↵
#define pi (double)2*acos(0.0)↵
#define minpq priority_queue <ll, vector<ll>, greater<ll>>↵
#define maxpq priority_queue<ll> ↵
void sout(){↵
cout<<endl;↵
}↵
template <typename T,typename... Types>↵
void sout(T var1,Types... var2){↵
cout<<var1<<" ";↵
sout(var2...);↵
}↵
/*******************************************************************/↵
↵
↵
ll arr[N];↵
ll pre[N];↵
ll tree[4*N];↵
ll n,a,b;↵
void build(ll s,ll e,ll ind=1){↵
if(s==e){↵
tree[ind]=pre[s];↵
return;↵
}↵
ll mid=(s+e)/2;↵
build(s,mid,2*ind);↵
build(mid+1,e,2*ind+1);↵
tree[ind]=max(tree[2*ind],tree[2*ind+1]);↵
}↵
ll getmax(ll s,ll e,ll l,ll r,ll ind=1){↵
if(e<l or s>r)↵
return -inf;↵
if(s>=l and e<=r)↵
return tree[ind];↵
ll mid=(s+e)/2;↵
ll a=getmax(s,mid,l,r,2*ind);↵
ll b=getmax(mid+1,e,l,r,2*ind+1);↵
return max(a,b);↵
}↵
ll getmax(ll l,ll r){↵
return getmax(0,n,l,r);↵
}↵
void solve(){↵
↵
cin>>n>>a>>b;↵
↵
rep(i,1,n+1){↵
cin>>arr[i];↵
}↵
↵
pre[0]=0;↵
rep(i,1,n+1){↵
pre[i]=pre[i-1]+arr[i];↵
}↵
↵
build(0,n);↵
ll ans=-inf;↵
for(ll i=a;i<=n;i++){↵
ll x=getmax(min(n,i+1),min(n,i+b-a));↵
x=x-pre[i];↵
x=max(x,0LL);↵
// sout("x",x);↵
ll loc=x+pre[i]-pre[i-a];↵
ans=max(ans,loc);↵
}↵
cout<<ans<<endl;↵
}↵
↵
int main(){↵
ios_base::sync_with_stdio(false);↵
cin.tie(NULL);↵
int t;↵
// cin>>t;↵
t=1;↵
while(t--){↵
solve();↵
}↵
}↵
~~~~~↵
↵
↵
</spoiler>↵
↵
In the first code the return value is -2*inf in the getmax function while it is -inf in the second code. Can anybody please help me figure out what is the problem?<br>↵
[Link to Problem](https://cses.fi/problemset/result/902905/)↵
↵
<spoiler summary="Code 1">↵
↵
~~~~~↵
#include<bits/stdc++.h>↵
using namespace std;↵
#define ll long long int↵
#define pii pair<ll,ll>↵
#define rep(i, begin, end) for (__typeof(end) i = (begin) - ((begin) > (end)); i != (end) - ((begin) > (end)); i += 1 - 2 * ((begin) > (end)))↵
#define vi vector<ll>↵
#define vii vector<pii>↵
#define all(x) x.begin(),x.end()↵
#define eb emplace_back↵
#define yes cout<<"YES"<<endl; return;↵
#define no cout<<"NO"<<endl; return;↵
#define flus fflush(stdin); fflush(stdout);↵
#define F first↵
#define S second↵
#define np next_permutation↵
#define inf 1e18↵
#define mod 1000000007↵
#define N 200100↵
#define pi (double)2*acos(0.0)↵
#define minpq priority_queue <ll, vector<ll>, greater<ll>>↵
#define maxpq priority_queue<ll> ↵
void sout(){↵
cout<<endl;↵
}↵
template <typename T,typename... Types>↵
void sout(T var1,Types... var2){↵
cout<<var1<<" ";↵
sout(var2...);↵
}↵
/*******************************************************************/↵
↵
↵
ll arr[N];↵
ll pre[N];↵
ll tree[4*N];↵
ll n,a,b;↵
void build(ll s,ll e,ll ind=1){↵
if(s==e){↵
tree[ind]=pre[s];↵
return;↵
}↵
ll mid=(s+e)/2;↵
build(s,mid,2*ind);↵
build(mid+1,e,2*ind+1);↵
tree[ind]=max(tree[2*ind],tree[2*ind+1]);↵
}↵
ll getmax(ll s,ll e,ll l,ll r,ll ind=1){↵
if(e<l or s>r)↵
return -2*inf;↵
if(s>=l and e<=r)↵
return tree[ind];↵
ll mid=(s+e)/2;↵
ll a=getmax(s,mid,l,r,2*ind);↵
ll b=getmax(mid+1,e,l,r,2*ind+1);↵
return max(a,b);↵
}↵
ll getmax(ll l,ll r){↵
return getmax(0,n,l,r);↵
}↵
void solve(){↵
↵
cin>>n>>a>>b;↵
↵
rep(i,1,n+1){↵
cin>>arr[i];↵
}↵
↵
pre[0]=0;↵
rep(i,1,n+1){↵
pre[i]=pre[i-1]+arr[i];↵
}↵
↵
build(0,n);↵
ll ans=-inf;↵
for(ll i=a;i<=n;i++){↵
ll x=getmax(min(n,i+1),min(n,i+b-a));↵
x=x-pre[i];↵
x=max(x,0LL);↵
// sout("x",x);↵
ll loc=x+pre[i]-pre[i-a];↵
ans=max(ans,loc);↵
}↵
cout<<ans<<endl;↵
}↵
↵
int main(){↵
ios_base::sync_with_stdio(false);↵
cin.tie(NULL);↵
int t;↵
// cin>>t;↵
t=1;↵
while(t--){↵
solve();↵
}↵
}↵
~~~~~↵
↵
↵
</spoiler>↵
↵
↵
<spoiler summary="Code 2">↵
↵
~~~~~↵
#include<bits/stdc++.h>↵
using namespace std;↵
#define ll long long int↵
#define pii pair<ll,ll>↵
#define rep(i, begin, end) for (__typeof(end) i = (begin) - ((begin) > (end)); i != (end) - ((begin) > (end)); i += 1 - 2 * ((begin) > (end)))↵
#define vi vector<ll>↵
#define vii vector<pii>↵
#define all(x) x.begin(),x.end()↵
#define eb emplace_back↵
#define yes cout<<"YES"<<endl; return;↵
#define no cout<<"NO"<<endl; return;↵
#define flus fflush(stdin); fflush(stdout);↵
#define F first↵
#define S second↵
#define np next_permutation↵
#define inf 1e18↵
#define mod 1000000007↵
#define N 200100↵
#define pi (double)2*acos(0.0)↵
#define minpq priority_queue <ll, vector<ll>, greater<ll>>↵
#define maxpq priority_queue<ll> ↵
void sout(){↵
cout<<endl;↵
}↵
template <typename T,typename... Types>↵
void sout(T var1,Types... var2){↵
cout<<var1<<" ";↵
sout(var2...);↵
}↵
/*******************************************************************/↵
↵
↵
ll arr[N];↵
ll pre[N];↵
ll tree[4*N];↵
ll n,a,b;↵
void build(ll s,ll e,ll ind=1){↵
if(s==e){↵
tree[ind]=pre[s];↵
return;↵
}↵
ll mid=(s+e)/2;↵
build(s,mid,2*ind);↵
build(mid+1,e,2*ind+1);↵
tree[ind]=max(tree[2*ind],tree[2*ind+1]);↵
}↵
ll getmax(ll s,ll e,ll l,ll r,ll ind=1){↵
if(e<l or s>r)↵
return -inf;↵
if(s>=l and e<=r)↵
return tree[ind];↵
ll mid=(s+e)/2;↵
ll a=getmax(s,mid,l,r,2*ind);↵
ll b=getmax(mid+1,e,l,r,2*ind+1);↵
return max(a,b);↵
}↵
ll getmax(ll l,ll r){↵
return getmax(0,n,l,r);↵
}↵
void solve(){↵
↵
cin>>n>>a>>b;↵
↵
rep(i,1,n+1){↵
cin>>arr[i];↵
}↵
↵
pre[0]=0;↵
rep(i,1,n+1){↵
pre[i]=pre[i-1]+arr[i];↵
}↵
↵
build(0,n);↵
ll ans=-inf;↵
for(ll i=a;i<=n;i++){↵
ll x=getmax(min(n,i+1),min(n,i+b-a));↵
x=x-pre[i];↵
x=max(x,0LL);↵
// sout("x",x);↵
ll loc=x+pre[i]-pre[i-a];↵
ans=max(ans,loc);↵
}↵
cout<<ans<<endl;↵
}↵
↵
int main(){↵
ios_base::sync_with_stdio(false);↵
cin.tie(NULL);↵
int t;↵
// cin>>t;↵
t=1;↵
while(t--){↵
solve();↵
}↵
}↵
~~~~~↵
↵
↵
</spoiler>↵
↵
