I don't know if I'm completely wrong, but reading the editorial for the Hacked Exam problem, maybe they overcomplicated the solutions for test sets 1 and 2. I just figured that, with T/F questions, adding a second student with a lower score doesn't change the expected value. So, the answer is to just replicate the best student (or the worst one inverted, for that matter). Does it make sense or I just got lucky to have passed with this idea? Thanks for any help! And please follow the code below.

string inv(string a) {
    string r;
    trav(x, a) {
        if(x == 'T') r += 'F';
        else r += 'T';
    }
    return r;
}

void run_test() {
    int n, q; read(n, q);
    int mx = 0;
    string ans;
    rep(k, n) {
        string a; read(a);
        int s; read(s);
        if(s <= q / 2) a = inv(a), s = q-s;
        if(s > mx) {
            mx = s;
            ans = a;
        }
    }
    cout << ans << " " << mx << "/1" << endl;
}