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By b14ck_5m0k3, history, 2 years ago, In English

char S[3], T[3]; cin >> S[0] >> S[1] >> S[2]; cin >> T[0] >> T[1] >> T[2]; why (S == T) gives no correct output, when it is?

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2 years ago, # |
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Because S and T refers to pointer to these arrays. If you compare them you will get the result of comparing two pointers, not arrays.