| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | tourist | 3985 |
| 2 | jiangly | 3814 |
| 3 | jqdai0815 | 3682 |
| 4 | Benq | 3529 |
| 5 | orzdevinwang | 3526 |
| 6 | ksun48 | 3517 |
| 7 | Radewoosh | 3410 |
| 8 | hos.lyric | 3399 |
| 9 | ecnerwala | 3392 |
| 9 | Um_nik | 3392 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | cry | 170 |
| 2 | maomao90 | 162 |
| 2 | Um_nik | 162 |
| 4 | atcoder_official | 160 |
| 5 | djm03178 | 158 |
| 5 | -is-this-fft- | 158 |
| 7 | adamant | 155 |
| 8 | Dominater069 | 154 |
| 9 | awoo | 153 |
| 10 | luogu_official | 152 |
I solved problems A–D, but I was quite slow, also I had two incorrect submissions for problem A, so my rating delta was -21.
If you want to watch my screencast and editorial, it will appear (UPD: has appeared) behind this link in several minutes: https://youtu.be/NuyV1LIMX3E; or in this box:
And, of course, my warmest congratulations to tourist on reaching 4000 rating points milestone!
Thanks, I always do appreciate your editorials!
edit : he mentioned that the number is prime for a brief second
Yes, it works only for an odd modulus, but I of course was proving it for an odd divisor of $$$g$$$ (proving that it only can be $$$1$$$, thus $$$g$$$ is a power of two).