Given two number N,M.Count the number of pair(i,j) such that LCM(i,j)=i*j.Here M,N<=10^9 and min(M,N)=10^6. How can I do this?
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3985 |
2 | jiangly | 3814 |
3 | jqdai0815 | 3682 |
4 | Benq | 3529 |
5 | orzdevinwang | 3526 |
6 | ksun48 | 3517 |
7 | Radewoosh | 3410 |
8 | hos.lyric | 3399 |
9 | ecnerwala | 3392 |
9 | Um_nik | 3392 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 169 |
2 | maomao90 | 162 |
2 | Um_nik | 162 |
4 | atcoder_official | 161 |
5 | djm03178 | 158 |
6 | -is-this-fft- | 157 |
7 | adamant | 155 |
8 | Dominater069 | 154 |
8 | awoo | 154 |
10 | luogu_official | 150 |
Given two number N,M.Count the number of pair(i,j) such that LCM(i,j)=i*j.Here M,N<=10^9 and min(M,N)=10^6. How can I do this?
Название |
---|
lcm(i, j) = i * j, when gcd(i, j) = 1.
so problem is -> how many pairs (i, j) such that gcd(i, j) = 1.
we can calculate it in min(n, m) with mebius function.
answer[i] = m[i] * f[i], where m[i] — value of mebius function(i), f[i] = function returning answer for i. in this problem it's (M / i) * (N / i)