Hi, Round #288 was Div. 1 and Div. 2 yesterday.
What happened ? Now I see it's a Div .2 Only contest !
Is this a mistake ? Or plan changed ?
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Hi, Round #288 was Div. 1 and Div. 2 yesterday.
What happened ? Now I see it's a Div .2 Only contest !
Is this a mistake ? Or plan changed ?
Название |
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And one more thing changed — it was scheduled on Jan/26 yesterday, and now it is on Jan/27.
I think some problems of Codeforces Round #288 (Div. 1) had some bug so codeforces admins changed the contest:))
clist.by
I believe, there are relevant reasons why announced schedule was changed, but announcement about the change would be nice too...
Yes, this is not a mistake. Due to some reasons we changed a schedule. Div1+Div2 round was moved to February 2nd, instead of it there will be a Div2 round on January 27th.
Round #290 will also be special since it is happening during the Petrozavodsk training camp and, as usual, we are going to reward top-N contestants from camp with Codeforces T-Shirts.
OOOH again T-shirts for contestants from the camp ONLY :((
What are your opinions about making div2 rounds rated for div1 also ?
I would like that but high rated users will just have a typing test which is a bit bad... i mean this is programming not a typing test competition
Not necessarily. Div2 only D/E can be good sometimes.
you are right but most of the div 2 only contests don't have problems that reds cant solve for example the last contest. anyway i myself would like to have rated div 2 contests
Why not to make 3 Divisions?
Like (<=1499), [1500,1900),(>= 1900)
YEAH , red coders compete against themselves :D
No, just 1-st division is gray, green
2-nd division is blue, purple
3-rd division is yellow, red
I should write a blog about it.
No... Then there would be div1(gray,green) only contests which even less people would want to do
I think you can take 2 or 3 problems from Div. 2(blue, purple) and just make 2 or 3 easier problems.
So you can do div.2 + div. 1 contests(or div. 2 + div. 3)
if they wanted to do this they didn't make div.1 and div.2 ...
This is what I think