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Consider a graph with 2 * n vertexes, vertex number i corresponds to situation when there are i people that have already been to finals. We have an arc (i, j) in this graph when we can send k of i experienced people in team and after it we have j experienced people (i.e. j = n + i - 2 * k, 0<=k <= i). It's obvious that each infinite path in this graph corresponds to some coach's strategy. One can prove, that one of optimal strategies is repetition of simple cycle in such a graph. That means you should find a cycle with lowest average weight in this graph. You can do it using combination of binary search and Bellman-Ford algorithm for finding cycles of negative weight.
By the way contestants found an O(n^2) solution, by unfortunately nobody have explained me why does it work yet. It would be great if somebody tells us it.