How to solve problem B ?
This problem looks similar to SPOJ-WATER
Someone please explain the approach to this problem?
Thank you!
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 168 |
2 | -is-this-fft- | 164 |
3 | Dominater069 | 160 |
4 | Um_nik | 159 |
5 | atcoder_official | 158 |
6 | djm03178 | 154 |
7 | adamant | 153 |
8 | awoo | 148 |
8 | luogu_official | 148 |
10 | TheScrasse | 146 |
How to solve problem B ?
This problem looks similar to SPOJ-WATER
Someone please explain the approach to this problem?
Thank you!
Name |
---|
I approached it in a way similar to Bellman Ford Algorithm . Take a matrix W and fill all the entries with infinity except the ones present in the border of the grid ie. i = 0 || i = (R - 1) || j = 0 || j = (C - 1) where i, j are the row index and column index respectively.
Now for each cell in the interior of the matrix water can come from 4 adjacent cells . We need to find the minimum of the incoming water from these cells and make this the new W[i][j] only if its greater than H[i][j]
For each cell with index i, j: min = min(W[x][y])
x, y adjacent to i, j and W[i][j] = max(min, H[i][j])
You need to run this relaxation for R * C times
My Java Code:
Link