Can we apply extend Extended Euclidean algorithm for negative numbers?
Like for 3*x-4*y=1 output will be x=3 , y=2 .
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3839 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3612 |
7 | Geothermal | 3569 |
7 | cnnfls_csy | 3569 |
9 | ecnerwala | 3494 |
10 | Um_nik | 3396 |
# | User | Contrib. |
---|---|---|
1 | Um_nik | 164 |
2 | maomao90 | 160 |
3 | -is-this-fft- | 159 |
4 | atcoder_official | 158 |
4 | cry | 158 |
4 | awoo | 158 |
7 | adamant | 155 |
8 | nor | 154 |
9 | TheScrasse | 153 |
10 | Dominater069 | 152 |
Can we apply extend Extended Euclidean algorithm for negative numbers?
Like for 3*x-4*y=1 output will be x=3 , y=2 .
Name |
---|
Why don't you just try it out?
Btw, even if it doesn't work, you can solve 3*x + 4*y = 1, receive the answer (x, y) to this modified problem, and the answer to your original problem will be (x, -y).
ok got it!, Thanks.