silentknight00's blog

How to find the larger elements to the left of every element in a given array?
By silentknight00, history, 6 years ago, In English

Given an array [1,3,4,2] we should get an array [0,0,0,2]. Can someone suggest a quick method for doing this

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6 years ago, # |
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This is essentially the inversion problem which can be solved using segment tree or binary indexes tree in O(nlogn). ( You can search for it online)

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6 years ago, # |
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Iterate from the left and imagine the array is the skyscrapers with height a[i]. Now we want to maintain all skyscrapers visible from i. To do so just maintain a stack. O(n).

stack<int>X;
for (int i = 0; i < n; i++)
{
	while (!X.empty() && a[X.top()] <= a[i])
	{
		X.pop();
	}
	if (X.empty())
		ans[i] = -1;
	else
		ans[i] = X.top();
	X.push(i);
}
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    6 years ago, # ^ |
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    But If I input 1 3 5 4, the output is 2. What am I missing?

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