Can someone provide an editorial of this problem or link to one that already exists (I was not able to find one via Google search)?
You can also check out this OEIS sequence!
# | User | Rating |
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1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
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1 | cry | 167 |
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3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
Can someone provide an editorial of this problem or link to one that already exists (I was not able to find one via Google search)?
You can also check out this OEIS sequence!
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Look at OEIS'
FORMULA
row:Since $$$1\le n\le 3000$$$, there is a simple $$$\mathcal{O}(n^2)$$$ solution:
Calculate $$$\mathrm{f}[n]$$$: number of connected graphs of $$$n$$$ nodes.
Formula: $$$\mathrm{f}[n]=2^{n(n-1)/2}-\sum_{i=1}^{n-1}\binom{n-1}{i-1}\mathrm{f}[i]2^{(n-i)(n-i-1)/2}$$$.
Calculate $$$\mathrm{g}[n]$$$: number of connected components in all possible graphs of $$$n$$$ nodes.
Formula: $$$\mathrm{g}[n]=\sum_{i=1}^{n}\binom{n-1}{i-1}\mathrm{f}[i](\mathrm{g}[n-i]+2^{(n-i)(n-i-1)/2})$$$.