can anyone help me to solve this problem https://onlinejudge.org/index.php?option=onlinejudge&Itemid=8&page=show_problem&problem=4628
→ Pay attention
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3831 |
| 3 | Radewoosh | 3646 |
| 4 | jqdai0815 | 3620 |
| 4 | Benq | 3620 |
| 6 | orzdevinwang | 3529 |
| 7 | ecnerwala | 3446 |
| 8 | Um_nik | 3396 |
| 9 | gamegame | 3386 |
| 10 | ksun48 | 3373 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | cry | 164 |
| 1 | maomao90 | 164 |
| 3 | Um_nik | 163 |
| 4 | atcoder_official | 160 |
| 5 | -is-this-fft- | 158 |
| 6 | awoo | 157 |
| 7 | adamant | 156 |
| 8 | TheScrasse | 154 |
| 8 | nor | 154 |
| 10 | Dominater069 | 153 |
→ Find user
→ Recent actions
Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Nov/05/2024 10:59:34 (j3).
Desktop version, switch to mobile version.
Supported by
The problem asks to count number of possible (x, y, z) such that
Ax + By + Cz = P, wherex, y, z >= 0. Also notice thatC/gcd(A, B, C) ≥ 200.If we iterate over all possible z, the problem simplifies to finding number of solutions for
Ax + By = P - Cz, whereminX = 0, maxX = (P - Cz) / B, minY = 0, maxY = (P - Cz) / A.This is a linear diophantine equation. You can learn how to solve this here.