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Why I am getting TLE for 2 base log function ?
By Moudud, history, 4 years ago, In English

Codeforces Round #648 (Div. 2) problem number C.

I am getting TLE in test case 8. This TLE is for log function that I have used in my code. The first number of test case:8 is "576460752303423487". The two base log of "576460752303423487" should be 58 but I am getting 59 that is why I am getting TLE.

long long x, xx; x=log2(n); xx=(ll)pow(2, x);

In this case xx is greater than n, but why? for this reason I am getting TLE. What should I do in this case?

My problem is here 1362C - Johnny and Another Rating Drop My submission is also here 82543228

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4 years ago, # |
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Firstly Make sure to use your own power function using Binary exponentiation which works in O(logn) time. Secondly,type caste the parameter of your log2() function to long double..i.e log2((long double)(x))..

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