How Can I solve this problem!https://toph.co/p/crypto-number Will be grateful if anyone can help. Thank You. TLE-O(q*sqrt(k)) time.
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 157 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
How Can I solve this problem!https://toph.co/p/crypto-number Will be grateful if anyone can help. Thank You. TLE-O(q*sqrt(k)) time.
Name |
---|
It's really a nice Number Theory problem.
In the problem statement you can note that r, p -both greater than 1 from it you can conclude the following:
From the previous observations, you can find the factors which are less than or equal the cube root in for-loop then you can check if there is a prime factor above the cube root or not.
In this way you can calculate prime factors for K with time complexity O($$$\sqrt[3]{K}$$$) then from the prime factors, you can find the divisors, and then the answer will be the frequency of the divisors in Array C.
AC solution
The Time Complexity O($$$Q\times\sqrt[3]{K}$$$)