for(int i=0;i<n;i++) { }
vs
for(int i=0;i<n;++i){ }
Both these loop run n times but we know that ++i and i++ are different. So can anyone explain what is happening in backend in gcc compiler using cpp? Thanks in advance
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3773 |
3 | Radewoosh | 3646 |
4 | ecnerwala | 3624 |
5 | jqdai0815 | 3620 |
5 | Benq | 3620 |
7 | orzdevinwang | 3612 |
8 | Geothermal | 3569 |
8 | cnnfls_csy | 3569 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 161 |
2 | maomao90 | 160 |
2 | awoo | 160 |
4 | atcoder_official | 157 |
5 | -is-this-fft- | 155 |
5 | nor | 155 |
5 | adamant | 155 |
8 | maroonrk | 152 |
8 | Um_nik | 152 |
10 | djm03178 | 146 |
for(int i=0;i<n;i++) { }
vs
for(int i=0;i<n;++i){ }
Both these loop run n times but we know that ++i and i++ are different. So can anyone explain what is happening in backend in gcc compiler using cpp? Thanks in advance
Название |
---|
Why do you expect them to have different runtimes?
++i
andi++
only differ if you actually use their values, something likej = ++i
(which is equivalent toj = i+1; i++
) vs.j = i++
(which is equivalent toj = i; i++
). Other than that they do exactly the same thingBasically, because the condition of stopping in your loop is checked before the increment of
i
, and after the increment ofi
(eitheri++
or++I
),I
increases by1
.