| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | tourist | 4009 |
| 2 | jiangly | 3839 |
| 3 | Radewoosh | 3646 |
| 4 | jqdai0815 | 3620 |
| 4 | Benq | 3620 |
| 6 | orzdevinwang | 3612 |
| 7 | Geothermal | 3569 |
| 7 | cnnfls_csy | 3569 |
| 9 | ecnerwala | 3494 |
| 10 | Um_nik | 3396 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Um_nik | 164 |
| 2 | maomao90 | 160 |
| 3 | -is-this-fft- | 159 |
| 4 | atcoder_official | 158 |
| 4 | awoo | 158 |
| 4 | cry | 158 |
| 7 | adamant | 155 |
| 8 | nor | 154 |
| 9 | TheScrasse | 152 |
| 10 | maroonrk | 151 |
There is a tree that consists of one node(the root) let it be (1).
There is some queries each query is either
find if x is ancestor of y.
make x a son of y(its guaranteed that y exist).
If the first query does not exist its easy to solve it using DFS but I am stuck at finding a solution for the whole problem.
How to solve this?
This problem can be solved using Binary Lifting. I recommend watching the tutorial on Binary Lifting by Algorithms Live! on Youtube if you don't already know it.