Привет! В 10.01.2022 17:35 (Московское время) начнётся Codeforces Round 764 (Div. 3) — очередной Codeforces раунд для третьего дивизиона. В этом раунде будет 7-8 задач, которые подобраны по сложности так, чтобы составить интересное соревнование для участников с рейтингами до 1600. Однако все желающие, чей рейтинг 1600 и выше могут зарегистрироваться на раунд вне конкурса.
Раунд пройдет по правилам образовательных раундов. Таким образом, во время раунда задачи будут тестироваться на предварительных тестах, а после раунда будет 12-ти часовая фаза открытых взломов. Мы постарались сделать приличные тесты — так же как и вы, мы будем расстроены, если у многих будут падать решения после окончания контеста.
Вам будет предложено 7-8 задач и 2 часа 15 минут на их решение. Одна из задач интерактивная. Не забудьте прочитать инструкцию по интерактивным задачам.
Штраф за неверную попытку в этом раунде будет равняться 10 минутам.
Напоминаем, что в таблицу официальных результатов попадут только достоверные участники третьего дивизиона. Как написано по ссылке — это вынужденная мера для борьбы с неспортивным поведением. Для квалификации в качестве достоверного участника третьего дивизиона надо:
- принять участие не менее чем в пяти рейтинговых раундах (и решить в каждом из них хотя бы одну задачу)
- не иметь в рейтинге точку 1900 или выше.
Независимо от того являетесь вы достоверными участниками третьего дивизиона или нет, если ваш рейтинг менее 1600, то раунд для вас будет рейтинговым.
Спасибо MikeMirzayanov за платформы, помощь с идеями для задач и координацией нашей работы. Задачи были придуманы и написаны командой Университета ИТМО: MikeMirzayanov, MisterGu, myav, Gol_D, Aris, senjougaharin и Vladosiya.
Также большое спасибо: itohdak, Yogi79, smtcoder, Ra16bit, Tlatoani, nigus, MrDindows, leaf1415, Kniaz, Alireza, mini4141, Jostic11, BitHashTech, An_yujin, oversolver и sodafago за тестирование раунда и весьма полезные замечания. Список тестеров будет пополняться.
Всем удачи!
UPD: Вот фото нашего коллектива во время ответа на ваши вопросы во время раунда:
UPD 2: Разбор
I wish every gray, become green! Good luck!
Can you please also wish for green to become cyan.
I wish every unrated become gray :heart_eyes:
The WA become AC!
Sorry, system testing doesn't work like that
thanks
Sorry but I had different plans.
Excited to participate in the first Div. 3 round of $$$2022$$$ and my first unrated round, yay!
Me too !
Good luck to everyone!
Interactive problems in div.3 round are epic.
Look forward to this contest!
Could we please have div3 rounds on the weekends? Most people in div3 probably have school Thanks
agree! I haven't had the contests on cf for a long time, although my score is low
I hate Div 3 so boring
Grandmasters find Div.2 boring ...
I wish my cyan color become blue!
You are blue already
Nope , It's a Christmas effect :)
Another permutation or binary search on problem C
Will there be div 4 contests in the near future
I tried solving a few interactive problems but got the idle limit exceeded! how to solve them?
I don't think there is any interactive problem that doesn't warn about flushing the output. Read the problem statement carefully from now on.
There is a link in the announcement of the round about interactive problems
Oh,no. I am very unhappy, because I will go to school on Tuesday. I want to have more rated, but I really won't have time. ):
me too..
i will have online classes :)
comeon dude, you gonna attend an online class.
I don't even know there was a thing called coding when i'am in school
The status of the problem I submitted 40 mins ago is still in queue. Is the same happening with all of you?
So excited to see blogs on Codeforces( this the second one). I haven't seen them for a year. (just a joke)
I wish my cyan color become blue!
I hope you done the best! Good luck for everyone!
Here we go again...............
First Div. 3 round in 2022!
All the best :) everyone, stay hydrated.
I hope I do good ;)
wow you guys are having fun (photo)
Thank you for this amazing round!
G has more submissions let's solve it.
can't solve G -> move to F
can't solve F -> move to E
can't solve E -> back to G ;_;
In the photo are all of these guys also the setters of this round or just for answering the question asked by everyone?
All the people in the photo are also the authors of the round
And which is you if it `s not a secret
I'm on the left
How to solve problem D,
I just thought of putting all the occurances of each letter into a set , & do the process optimally for k times , can someone help me, I know my solution will fail at cases like aaaaaaa, k = 2.. :
Hint — Binary search for the answer
Binary Search is not necessary.
Count freq of each character for i=1:26
if (freq[i]%2==1) // one of the occurrences of this character can be part of a palindrome at the middle position
the rest sigma(freq[i]/2) pairs of characters can be splitted evenly between each of the k palindromes.
https://codeforces.net/contest/1624/submission/142239619
Can be also solved greedily.
Count occurences of letters in original string and count number of singles and doubles.
(doubles — how many pairs of letters there are, singles — number of letters minus doubles * 2).
Knowing singles and doubles values you can calculate solution.
There's no need for maintaining sets, you only need the counts of the possible number of pairs you can form for all the letters.
This divided and then multiplied by k (integer division) will give the number of pairs that will be assigned to each color.
If there are still other letters which have not been selected in any of the selected pairs yet, you can add 1 such char to the string of each color (eg: cac).
My Submission.
DAAAMN, I had so much fun solving E (although I didn't quite finish it).
I thought that out of all solutions we were supposed to pick one that has least segments — which imo is even better problem (not sure if harder then original though).
Actually my solution to that problems is O(n * m * n). Does anybody know how to solve this variant in better time?
I have idea :)
I somehow frequently mess up the easier problems smh. Got 3 WAs on B when it was just basic implementation, and wasted a lot of time on D, when my first instinct was greedy with priority queue, but ended up trying to solve it with Binary Search unsuccessfully and finally solved it with my first instinct smh.
Great problems though.
It’s so great to solve all problems without a WA for the first time!
Solved C using Kuhn's algorithm... LMAO :D
142249902
Same. The first thing that came to my mind after reading the problem is bipartite matching.
I solved it using priority queue :)
Could you explain your approach, please? I just don't see how's this problem about bipartite matching...
For each number a_i in the array, consider the set of numbers from 1 to n that appear when you keep doing floor(a_i/2).
For example, a_i=25 and n=5, then the set is {1,3}.
Then we have a bipartite graph of positions and the numbers that could go there. As we can only have one number in each position, this implies a bipartite matching in the graph.
how to solve F? Tried something close to a binary search but got WA.
Yes. Just binary search.
I felt crippled at binary search in F :))
F made me realise that if my usual binary search implementation isn't suitable for the problem, then I am screwed :)
This round is amazing! I really enjoy the problems. Thank you very much :)
Video Tutorial B:https://www.youtube.com/watch?v=W-y8gQFrFOY
Video Tutorial C:https://www.youtube.com/watch?v=6k8YudeK_04
NOice:))
Why is G so simple, although I won't
Interactive problems and BinarySearchForces.
Name a more iconic duo. I'll wait.
Why? Just why??
Got the binary search idea for D but did not know how to handle the odd case
I solved it now
Don't know why but That photo looks like a team of hackers from some Hollywood movie lol :/
What I learned from this contest . Take all inputs before even thinking of outputting an edge case
How foolish can I be at times
Great round!
Imagine not noticing this line in problem D.
Are exceeded queries in interactive problems always tagged WA. I kept on thinking about issues with the logic when my solution was actually asking for an extra query than needed.
You can have something like this in your code. Now you get MLE if you ask more than 10 queries.
Thanks. Looks like a very useful trick.
You can just keep an assert statement which will give you a runtime error if you exceed the query limit.
Hi
Great round. I really enjoyed solving the problems, especially problem G.
In F the condition that x < n was written on top, and I skip it so in 1h30m I can't reduce 11 queries to 10 queries lol :L rip everyone liked me :(
In the exact same boat as you lol. Hurts a lot since it's a rated contest for me.
yea but howcome the answer for the first testcase is 3, it should be less than n right Aris?
How about you read the goddamned statement before trying to point fingers nowhere?
this command assigns x=x+c
Surprise surprise, the value will and can change
well the statement wasn't clear for me, it hurts to be polite !?
Did reading the statement hurt as much?
Really, I kinda grew tired of seeing comments toward some issue that has been carefully crafted, such as this contest / problem, being like " well, you know what, problem-author, I think that you are an idiot, the testers are idiots, and everybody that solved this problem are idiots (>500), and I really think I'm right ---- there is a grave inconsistency of some form in your statement that undermines the intended solution ". Really, there might be times when such grave mistakes might pass, but let's face it: this situation would never happen, especially with such a well written contest.
Moreover, the excuse of "the problem statement wasn't clear for me" is so underwhelming. It's not as if the statement is about Alice and Bob visiting a pillow case shop where they have to cut pillow cases in half, and to some people it might not be obvious that for some reason you can't cut pillowcases along the thickness line or some stupid not-inherent observation like that — the problem statement is as formal as it can be written, every detail should be in the statement, so yet again, we find ourselves back at square one:
"is it really the problem setters fault or is it mine?"
If after rereading the statement many times, very carefully, you conclude that it could very much potentially be the problem setters fault, you should alert ''authorities'' and then point out the inconsistency. But that comment was unbased on any evidence, it was made only because youbwere too entitled to try and figure out the problem statement on your own, immediately after hitting bumps you decised to blame one of the problem setters.
So, yeah, I do admit that I was rude, but probably I didn't offend the work of some people that spanned maybe weeks or months, and only some careless person.
lool, did you even read whatever you pasted? I didn't offend anyone, I was asking a question, I didn't complain about the problem during/after the contest, I also didn't blame the problem writer, nothing happened like that.
what I really see is you trying to mimic um_nik's attitude, and it just doesn't look good.
So at this point, I'm either illiterate (which I'm not, since I was able to read the problem statement), you're trying to run away from conflict, or this ( "how come {this}, when {thing that should contradict the other}, right Aris ?" ) is some funny inside joke that I'm not in on.
For my peace and quiet, I will assume the last although I strongly believe it is the second option, case in which I really hope you actually read what I wrote
Also, is forming an opinion, argumenting it (with proof, to show what I actually understood and what led me to that cause) and then asking the opposite party what is their argument really um_nik's behaviour? If so, damn, he should get a patent for "behaviour". Sorry for trying to point out anything, and moreover, sorry for not leading your example in making a shitty argument towards a possible point to assert my dominance over.. whatever
Congratulations you're not illiterate, because you were able to read the problem statement.
Try to have peace in your life, good luck ;)
Was problem G taken from somehwere? It has way too many submissions.
Apparently, the main idea for the problem was the same as one of the ideas used in one of the problems in yesterday's Codechef Snackdown Finals.
hi bro
Right the logic is somewhat similar.
Nice Div.3 contest. Thank you!
Does "wrong answer Jury has answer, but participant doesn't (test case 3648)" means my answer is -1 but Jury is not or my answer is empty? Moreover, I just touch the length of segment must be 2 or 3 in problem E, but I implement it so complex, and finally get a wa2 without anymore clue... https://codeforces.net/contest/1624/submission/142294335
Yes, it means that the jury was able to find an answer, but you could not. For example, consider this testcase.
The required phone number is just a duplicate of the existing numbers. Hence, an answer definitely exists. However, your code produces $$$-1$$$.
I get why my algorithm is fake. Thanks a lot~
Video Solutions for anyone looking
This round was very special for me because for the first time I have solved a problem in live contest. I loved it. I am happy and only I know how happy I am. We need more division 3 contest.
Got a binary search solution for F, but it gets W/A on 6th test. Can anyone explain mistate or send a test that fails https://codeforces.net/contest/1624/submission/142288442 Thanks!
Jury printed n as: 5
Jury has picked x as: 3
Participant asked to add: 2, x has now become: 5
Jury responded with 1
Participant asked to add: 4, x has now become: 9
Jury responded with 1
Participant has guessed the current x as: 10
The guess was incorrect.
Amazing contest!
The problems were very interesting, especially problem G!
oops, I tried to do something more clever with F and figure out the bits one by one. was wondering why I was retarded for the past hour lol
I'am gray. But it is showing under 'only unrated' in my profile's contest page.
just wait
Upsolved E by matching a string using extended patterns (with code) within regexes (DFS simulation). Perl: 142302044.
Solution to Problem C using "Max Flow" :)142222070
Resource For Dinic's algorithm
If someday there will be an super-algorithm to solve all problems, everyone will be using that !
That will kill the very fun of problem solving
nice contest
Please help, For which TC I am getting WA (Problem C) Your text to link here... thanks in advance
We already have $$$[3, 4, 5, 6, 7]$$$. We can create 2 by dividing 4, and we can create 1 by dividing 7 repeatedly.
O(32(n+m)) was not acceptable in problem G?
My O(30 * M) code got accepted. https://codeforces.net/contest/1624/submission/142284695
Is it not O(30*(n+m))?
I am going through m edges for every bit so its O(30M). Your code gets accepted(1900ms) if you start with 29th bit.
Bad luck!
for E consider the following test case
2 4
1278
6935
7878
output->
2
3 4 1
3 4 1
I wanted to ask whether the output is correct? that is can we repeat a particular segment?
UPD-> Got it, read the announcement now:)
Editorial?
Can somebody please explain me why I didn't get any rating for participation in this contest?
I don't want to create a new post, so desperately hoping my comment here will get some attention.
I'm a newbie in competitive programming and just recently joined Codeforces. I hoped to start acquiring rating and earning experience by participating in Div.3 contests. Even if this contest (#764) is the second contest I'm participating (the first one was Hello 2022 where I solved just one problem), I assumed I'm qualified to be rated in Div.3 contests. However, this one didn't affect my rating at all.
Please, help me understand the rules of the system!
Ratings haven't been updated yet. Normally in div3 rounds, there is a 12-hour hacking phase. When the hacking phase is done, ratings will be updated in a couple of hours.
you can always wait until the record of this contest appears in your contest history.
I got wrong answer "wrong answer Jury has answer, but participant doesn't" in Problem E. I use greedy and kmp algorithm. I match target number as much as possible. Once match is one, i will backtrace one and rematch again. If it can't match target number or one of the segments is one, it will break and output "-1". My algorithm complexity would timed out. But is this algorithm is wrong? I try many tests and verify my answer is correct.
No, this is correct, you must have made a mistake somwhere.
I've done something very similar and it fails only on big tests (tle).
Okay, I overestimated your solution. To make up for my mistake here is a test where your solution is failing :).
1 1 10 abcxcdxdcx abcdcdcdcd
Thank you for your help :)
Still rating is not updated
it's system testing. I guess too many successful hacks.
Again! I turned into a zombie after solving 2 problems
Are there any problems with the players ranked 212？Can anybody check it?
I saw someone was gonna stream the solution of these but I could not find it now, do you have that link?
https://www.youtube.com/watch?v=0SbJnUiSD9E&ab_channel=Harisamsharma
Why this contest is unrated for me? Wasn't it rated for all participant under rating 1600?
Instead of killing your nerve cells in waiting you can always use CF predictor (it is quite accurate)
rating changes when??
after removing cheaters. Wait... :)
I know this isn't the intended solution of C, but can someone explain why this wouldn't work?
My Submission (WA on 5).
We already have $$$[1, 5, 6, 7, 8]$$$.
We need to create $$$[2, 3, 4]$$$ from $$$[1, 6, 8]$$$.
We can definitely create $$$[3, 4]$$$ from $$$[6, 8]$$$.
But, you won't be able to create the remaining $$$2$$$.
Time limit of Problem G is not java friendly ;(
This was my submission — 142369596 for 1624E - Masha-forgetful.
The checker log gives me the following message:
wrong answer Integer parameter [name=r] equals to 4, violates the range [1, 2] (test case 249)Does this mean that my code prints r = 4 for some line while the length of the number is 2? (correct me if I'm wrong)
I can't seem to find my mistake. Any help would be appreciated!
No, it doesn't.
You forgot to print the number of segments used if $$$m$$$ is 2 or 3.
For example, one failing test case can be.
A possible answer is
but your code would produce
So, in the original testcase, the jury thinks that you're going to print $$$L$$$ segments, while you actually intended to print just one. Hence the WA.
Просьба тем, кто решал на python
Если вам удалось решить G без TL, подскажите, пожалуйста или поделитесь решением
Вы можете посмотреть на все сданные решения на питоне с помощью фильтра. Попробуйте использовать алгоритм Крускала(как я понял, вы его не используете), он должен быть побыстрее других.
Вот код, сразу извините, если у вас вытекут глаза от кода, я на питоне почти не пишу :)
Большое спасибо.Думаю надо прочитать Крускала и станет яснее :)
Забавно, вроде сделал все тоже самое, но мое решение работает почти 2 секунды, а написанное Вами — 1600 мс. Дьявол в деталях :)
Еще раз спасибо, в итоге и разобрался, и реализовал
This is my submission for problem E 142402622. The checker log gives the message
wrong answer Answer phone is not "s" (test case 532). I am not able to understand the meaning of this message and also not able to find the bug in my code. Could somebody please help?Substring $$$[2,4]$$$ in the second string is $$$[000]$$$ while the required phone number has a prefix $$$[001]$$$
MikeMirzayanov my submission 142240970 coincides with 142233988 from bernardo_amorim, after looking at his code I think it was triggered because of the main, he have a similar style to mine and this problem is a classical 15 lines problem, I do not know this guy and I did not cheat in any way!!. Please remove the cheating accusation. I saw that he complained too here https://codeforces.net/blog/entry/8790?#comment-876676.
The hardest problem of this round: Figuring out what the pun in problem F's name is.
I was like: "Interac-dive? But the problem has got nothing to do with diving"
It's probably 'Interac-div-e' where 'div' stands for the division operation.
The girl on the bottom-left looks cute!
Agree with you :)