Problem Link:

Contest
Question

Author & Testor: Sarvesh_Powar
Editorialist:Madara_Uchia

DIFFICULTY:

CAKEWALK

PREREQUISITES:

Basic Arithmatics

PROBLEM:

For the Survival of PANDORA planet, Pandora creatures have to play two football matches with Humans.

For that, you have given 4 integers A, B, C, and D.

In which A and B denotes the Score of PANDORA creatures and human respectively in match 1.

Similarly, C, and D denotes the Score of PANDORA creatures and human respectively in match 2.

You have to decide whether PANDORA creatures will survive in this domination or not.

EXPLANATION:

      In this problem, They are having 2 matches each and we are provided with their scores. A and C are the scores of PANDORA creatures whereas B and D are the scores of humans in matches 1 and 2 respectively.
      Therefore, Pandora creatures have to score more than humans to survive, i.e. A+C should be greater than B+D then the output should be "SURVIVED" (without the quotation marks and in upper case) and if humans scored more than PANDORA creatures, i.e. B+D is greater than A+C then the output should be "NOT SURVIVED" (without the quotation marks and in upper case)
else both humans and creatures scored the same goals in both matches aggregately i.e. A + C == B + D, it'll be tied and the output should be "NA" (without the quotation marks and in upper case)

TIME COMPLEXITY:

O(1) per test case.

CODE:

//JAY SHREE RAM

#include <bits/stdc++.h>

using namespace std;
#define FORi(i, start, n) for (int i = start; i < n; i++)
typedef long long ll;
#define pb push_back
#define hanji cout << "Yes" << endl;
#define naaji cout << "No" << endl;
const ll M = 1e9 + 7;
#define fast() ios_base::sync_with_stdio(false), cin.tie(NULL)
#define sp ' '
ll mod(ll a)
{
  return ((a % M) + M) % M;
}
ll add(ll a, ll b)
{
  return mod(mod(a) + mod(b));
}
ll mul(ll a, ll b)
{
  return mod(mod(a) * mod(b));
}

int main()
{

  fast();

  ll a, b, c, d;
  cin >> a >> b >> c >> d;

  ll creatureScore = a + c;
  ll humanScore = b + d;

  // If both humans and PANDORA creatures scored equal
  if (creatureScore == humanScore)
    cout << "NA" << endl;

  // If PANDORA creatures scored more than humans i.e They were able to survive
  else if (creatureScore > humanScore)
    cout << "SURVIVED" << endl;

  // If PANDORA creatures scored less than humans i.e. They were not able to survive
  else
    cout << "NOT SURVIVED" << endl;

  return 0;
}