This is the editorial for the first edition of the International Odoo Programming Contest
Author: pauloamed
105056A - Potential Odoo Email
Editorial
...
Solution
#include<bits/stdc++.h>
using namespace std;
int main() {
const string suffix = "@odoo.com";
string s; cin >> s;
int last_pos_at = s.find_last_of('@');
if(s.size() < suffix.size()) {cout << "no\n"; return 0; }
if(last_pos_at == string::npos) {cout << "no\n"; return 0;}
if(last_pos_at < 2 || last_pos_at > 4) {cout << "no\n"; return 0;}
if(s.substr(last_pos_at) != suffix) {cout << "no\n"; return 0; }
for(int i = 0; i < last_pos_at; i++) {
if(s[i] < 'a' || s[i] > 'z') {cout << "no\n"; return 0; }
}
cout << "yes\n";
}
Author: pauloamed
Editorial
...
Solution
#include<bits/stdc++.h>
using namespace std;
int main() {
int T; cin >> T;
const string odoo = "ODOO";
while(T--) {
string s; cin >> s;
int ans = INT_MAX;
for(int i = 0; i + 3 < s.size(); ++i) {
int diff = (
(s[i] != odoo[0]) +
(s[i + 1] != odoo[1]) +
(s[i + 2] != odoo[2]) +
(s[i + 3] != odoo[3])
);
ans = min(ans, diff);
}
cout << ans + s.size() - 4 << "\n";
}
}
Author: ghrissiraouf
Editorial
...
Solution
#include <bits/stdc++.h>
#define inf 1e9
struct node {
int id;
int p;
int c; // c == inf to put it after the module if they have the same position
node(int _id, int _p, int _c = inf) {
id = _id;
p = _p;
c = _c;
}
};
bool compare(node n1, node n2) {
if (n1.p == n2.p) {
return n1.c < n2.c;
}
return n1.p < n2.p;
}
using namespace std;
vector<string> solve() {
//freopen("c.txt", "r", stdin);
int n, m, k;
cin>>n>>m>>k;
vector<node> v;
int cap[m][n];
memset(cap, -1, sizeof cap);
unordered_map<string, int> module_id_per_name;
vector<string> module_name_per_id(n);
string s;
int c, p;
int id = -1;
for (int i=0 ; i<n ; i++) {
cin>>s>>c>>p;
module_id_per_name[s] = ++id;
module_name_per_id[id] = s;
v.push_back(node(id, p, c));
}
int num;
for (int i=0 ; i<m ; i++) {
cin>>num>>p;
num--;
v.push_back(node(num, p));
}
for (int i=0 ; i<k ; i++) {
cin>>num>>s>>c;
num--;
cap[num][module_id_per_name[s]] = c;
}
sort(v.begin(), v.end(), compare);
stack<node> st;
stack<node> st2;
n = v.size();
for (int i = 0 ; i<n ; i++) {
if (v[i].c == inf) { // virus
int vid = v[i].id;
while(!st.empty()) {
node t = st.top();
int mid = t.id;
int vc = cap[vid][mid];
if (vc == -1) { // can't collide
st2.push(t);
st.pop();
} else {
int mc = t.c;
if (vc == mc) {
st.pop();
break;
} else if (vc < mc) {
st.top().c -= vc;
break;
} else {
st.pop();
}
}
}
while(!st2.empty()) {
st.push(st2.top());
st2.pop();
}
} else {
st.push(v[i]);
}
}
vector<string> ans;
while(!st.empty()) {
ans.push_back(module_name_per_id[st.top().id]);
st.pop();
}
return ans;
}
int main() {
auto a = solve();
cout << a.size() << endl;
for(auto &u:a){
cout << u << " ";
}
return 0;
}
Author: NatanSG
Editorial
...
Solution
#include<bits/stdc++.h>
using namespace std;
template<typename T> ostream& operator<<(ostream &os, const vector<T> &v) { os << "{"; for (typename vector<T>::const_iterator vi = v.begin(); vi != v.end(); ++vi) { if (vi != v.begin()) os << ", "; os << *vi; } os << "}"; return os; }
template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { os << '(' << p.first << ", " << p.second << ')'; return os; }
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
#define optimize ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define endl "\n"
#define fi first
#define se second
#define pb push_back
#define all(x) x.begin(),x.end()
#define ms(x,a) memset(x,a,sizeof(x))
#define INF 0x3f3f3f3f
#define INFLL 0x3f3f3f3f3f3f3f3f
#define mod 1000000007LL
#define MAXN 200010
/* -------------------------------- Solution starts below -------------------------------- */
ll N, T;
ll A[MAXN];
bool check(ll m) {
priority_queue<ll, vector<ll>, greater<ll>> pq;
for(int i = 0; i < m; i++) {
pq.push(0);
}
for(int i = 0; i < N; i++) {
ll x = pq.top();
pq.pop();
if(x + A[i] > T) return false;
pq.push(x + A[i]);
}
return true;
}
void solve() {
ll l = 1, r = MAXN;
while(l < r) {
ll m = (l + r) / 2;
if( check(m) ) r = m;
else l = m + 1;
}
if(l == MAXN) {
l = -1;
}
cout << l << endl;
}
int main() {
optimize;
cin >> N >> T;
for(int i = 0; i < N; i++) {
cin >> A[i];
}
solve();
return 0;
}
Author: Mtaylor
Editorial
...
Solution
// Mtaylor
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define fi first
#define se second
#define mp make_pair
#define endl '\n';
#define sz(x) ((int)(x).size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
void dbg_out() { cerr << endl; }
template <typename Head, typename... Tail>
void dbg_out(Head H, Tail... T) {
cerr << ' ' << H;
dbg_out(T...);
}
#define dbg(...) cerr << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__)
typedef long long ll;
const int N = 3e5 + 5;
int t;
int n;
ll a[N];
ll sum[N];
vector<int> p;
void test_case() {
cin >> n;
p.clear();
for (int i = 0; i < n; i++) {
cin >> a[i];
}
ll s = 0;
sum[n] = 0;
p.pb(n);
ll cur = 0;
ll ans = 0;
for (int i = n - 1; i >= 0; i--) {
s += a[i];
sum[i] = s;
while (p.size() && sum[p.back()] > s) {
int y = p.back();
p.pop_back();
int x = -1;
if (p.size()) {
x = p.back();
}
if (x != -1) {
cur -= sum[y] * (x - y);
} else {
cur -= sum[y] * (n + 1 - y);
}
}
int x = -1;
if (p.size()) {
x = p.back();
}
if (x != -1) {
cur += sum[i] * (x - i);
} else {
cur += sum[i] * (n + 1 - i);
}
p.push_back(i);
ans -= cur;
ans += sum[i] * (n - i + 1);
}
cout << ans << endl;
}
int main() {
// freopen("input.txt", "r", stdin);
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int T = 1;
cin >> T;
while (T--) {
test_case();
}
return 0;
}
Author maghrabyJr_
Editorial
...
Solution
#include <bits/stdc++.h>
using namespace std;
#define int long long
int n, k, q;
struct segmentTree{
vector<int> values;
int sz = 1;
void init(int n){
while(sz < n) sz *= 2;
values.resize(2 * sz, 1);
}
void set(int i, int v, int x, int lx, int rx){
if(rx - lx == 1){
values[x] = v % k;
return;
}
int m = (lx + rx) >> 1;
if(i < m)
set(i, v, 2 * x + 1, lx, m);
else
set(i, v, 2 * x + 2, m, rx);
values[x] = values[2 * x + 1] * values[2 * x + 2] % k;
}
void set(int i, int v){
set(i, v, 0, 0, sz);
}
int ans(int x, int lx, int rx, int ai){
if (rx - lx == 1){
return lx;
}
int m = (lx + rx) >> 1;
if (values[2 * x + 1] * ai % k == 0){
return ans(2 * x + 1, lx, m, ai);
}
return ans(2 * x + 2, m, rx, ai * values[2 * x + 1] % k);
}
int ans(int x){
if (x % k == 0)
return 0;
if (values[0] * x % k != 0)
return -1;
return ans(0, 0, sz, x);
}
};
const int N = 2e5 + 10;
vector<int> adj[N];
int ans[N], a[N];
vector<pair<int,int>> updates[N];
segmentTree st;
void dfs(int node, int p){
for (auto [i, y] : updates[node]){
st.set(i, y);
}
ans[node] = st.ans(a[node]);
for(int ch : adj[node]){
if(ch != p)
dfs(ch, node);
}
for (auto [i, y] : updates[node]){
st.set(i, 1);
}
}
int32_t main() {
cin.tie(0);
cin.sync_with_stdio(0);
cin>>n>>k>>q;
for(int i = 0; i < n; i++){
cin>>a[i]; a[i] %= k;
}
for(int i = 1; i < n; i++){
int p; cin>>p; --p;
adj[p].push_back(i);
}
for(int i = 1; i <= q; i++){
int x, y;
cin>>x>>y;
updates[x - 1].push_back({i, y});
}
st.init(q + 10);
dfs(0, 0);
for(int i = 0; i < n; i++){
cout<<ans[i]<<' ';
}
}
Author: kinhosz
Editorial
...
Solution
v_pr = []
v_bonus = []
adj = []
query = []
offline = []
ans = []
added = []
parent = []
class Line:
def __init__(self, m, c):
self.m = m
self.c = c
class CHTPersistent:
def __init__(self):
self.hull = []
self.SZ = 0
self.version_idx = []
self.version_sz = []
def inter(self, t1, t2):
ret = (t2.c - t1.c)/(t1.m - t2.m)
return ret
def add2(self, curr):
self.version_sz.append(self.SZ)
if self.SZ > 1:
s = 0
e = self.SZ-1
while s < e:
p = (s+e)//2
temp = self.hull[p+1][-1]
temp2 = self.hull[p][-1]
point = self.inter(temp, temp2)
point2 = self.inter(temp, curr)
if point < point2:
s = p+1
else:
e = p
self.SZ = s+1
if len(self.hull) == self.SZ:
x = []
self.hull.append(x)
self.hull[self.SZ].append(curr)
self.version_idx.append(self.SZ)
self.SZ+=1
def add(self, m, c):
self.add2(Line(m, c))
def query(self, find):
s = 0
e = self.SZ-1
while s < e:
p = (s+e)//2
point = self.inter(self.hull[p][-1], self.hull[p+1][-1])
if point < find:
s = p+1
else:
e = p
ret = (self.hull[s][-1].m * find) + self.hull[s][-1].c
return ret
def rollback(self):
self.SZ = self.version_sz[-1]
self.version_sz.pop()
self.hull[self.version_idx[-1]].pop()
self.version_idx.pop()
def size(self):
return self.SZ
cht = CHTPersistent()
def dfs(u):
while u != -1:
if added[u] == False:
cht.add(v_pr[u], v_bonus[u])
for q_id in offline[u]:
d = query[q_id]
ans[q_id] = cht.query(d)
added[u] = True
if len(adj[u]) > 0:
v = adj[u][-1]
adj[u].pop()
u = v
else:
cht.rollback()
u = parent[u]
def main():
txt = input().split()
n = int(txt[0])
q = int(txt[1])
for i in range(n):
adj.append([])
v_pr.append(0)
v_bonus.append(0)
offline.append([])
added.append(False)
parent.append(0)
for i in range(q):
ans.append(0)
root = -1
for i in range(n):
txt = input().split()
idd = int(txt[0])
pid = int(txt[1])
pr = int(txt[2])
bonus = int(txt[3])
idd -= 1
pid -= 1
v_pr[idd] = pr
v_bonus[idd] = bonus
if pid == -1:
root = idd
else :
adj[pid].append(idd)
parent[idd] = pid
for i in range(q):
txt = input().split()
idd = int(txt[0])
d = int(txt[1])
idd -= 1
query.append(d)
offline[idd].append(i)
dfs(root)
for i in range(q):
print(ans[i])
if __name__ == "__main__":
main()
Author: Mtaylor
Editorial
...
Solution
// Mtaylor
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define fi first
#define se second
#define mp make_pair
#define endl '\n';
#define sz(x) ((int)(x).size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
void dbg_out() { cerr << endl; }
template <typename Head, typename... Tail>
void dbg_out(Head H, Tail... T) {
cerr << ' ' << H;
dbg_out(T...);
}
#define dbg(...) cerr << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__)
typedef long long ll;
const int N = 1e5 + 5;
const int E = 1e6 + 5;
#define neig(u, v, e, g) \
for (int e = g.head[u], v; ~e && ((v = g.to[e]), 1); e = g.nxt[e])
class ADJ {
public:
int head[E], to[E], nxt[E], n, edgcnt = 0;
ll cst[E];
void addEdge(int a, int b, int c = 0) {
nxt[edgcnt] = head[a];
head[a] = edgcnt;
to[edgcnt] = b;
cst[edgcnt] = c;
edgcnt++;
}
void addBiEdge(int a, int b, int c = 0) {
addEdge(a, b, c);
addEdge(b, a, c);
}
void init(int _n) {
n = _n;
memset(head, -1, n * sizeof(head[0]));
edgcnt = 0;
}
} adj;
set<int> tree[4 * N];
int n, k, q;
int v[N];
int t, p, u;
set<int>::iterator it;
int getVal(int id, int k) {
if (!tree[id].size()) return -1;
it = tree[id].lower_bound(k);
if (it != tree[id].end()) {
return *it;
}
return *tree[id].begin();
}
int mrg(int x, int y, int k) {
if (x == -1 || y == -1) return max(x, y);
if (x >= k && y >= k) {
return min(x, y);
}
if (x < k && y < k) {
return min(x, y);
}
return max(x, y);
}
int queryPosition(int qp, int k, int id = 0, int ns = 0, int ne = n - 1) {
int rs = getVal(id, k);
if (ns == ne) {
return rs;
}
int l = 2 * id + 1;
int r = l + 1;
int md = ns + (ne - ns) / 2;
if (qp <= md) {
rs = mrg(rs, queryPosition(qp, k, l, ns, md), k);
} else {
rs = mrg(rs, queryPosition(qp, k, r, md + 1, ne), k);
}
return rs;
}
void updateRange(int qs, int qe, int p, int to_ins, int id = 0, int ns = 0,
int ne = n - 1) {
if (qs > ne || qe < ns) return;
if (qs <= ns && qe >= ne) {
if (to_ins) {
tree[id].insert(p);
} else {
tree[id].erase(p);
}
return;
}
int l = 2 * id + 1;
int r = l + 1;
int md = ns + (ne - ns) / 2;
updateRange(qs, qe, p, to_ins, l, ns, md);
updateRange(qs, qe, p, to_ins, r, md + 1, ne);
}
class HLD {
public:
vector<int> par, sze, dpth, ndToIdx, chHead, heavyChld, idxToNd;
int n, curPos;
HLD() {}
void run(ADJ &adj) {
n = adj.n;
curPos = 0;
par.assign(n, -1);
sze.assign(n, 0);
dpth.assign(n, 0);
ndToIdx.assign(n, 0);
chHead.assign(n, 0);
heavyChld.assign(n, 0);
idxToNd.assign(n, 0);
calcsz(0, adj);
HLD_util(0, adj);
}
void calcsz(int u, ADJ &adj) {
heavyChld[u] = -1;
sze[u] = 1;
int mx = 0, mxv;
neig(u, v, e, adj) {
if (par[u] == v) continue;
par[v] = u;
dpth[v] = dpth[u] + 1;
calcsz(v, adj);
if (sze[v] > mx) {
mx = sze[v];
mxv = v;
}
sze[u] += sze[v];
}
if (mx * 2 > sze[u]) {
heavyChld[u] = mxv;
}
}
void HLD_util(int u, ADJ &adj, int c = 0) {
if (u == -1) return;
idxToNd[curPos] = u;
ndToIdx[u] = curPos++;
chHead[u] = c;
HLD_util(heavyChld[u], adj, c);
neig(u, v, e, adj) {
if (v == par[u]) continue;
if (v == heavyChld[u]) continue;
HLD_util(v, adj, v);
}
}
int lca(int u, int v) {
while (chHead[u] != chHead[v]) {
if (dpth[chHead[v]] > dpth[chHead[u]]) swap(u, v);
u = par[chHead[u]];
}
if (dpth[u] > dpth[v]) swap(u, v);
return u;
}
int dist(int u, int v) { return dpth[u] + dpth[v] - 2 * dpth[lca(u, v)]; }
// make sure to update the return type based on the type of the segment
// tree
int query(int u, int k) { return queryPosition(ndToIdx[u], k); }
void update(int u, int v, int p, int to_insert) {
while (chHead[u] != chHead[v]) {
if (dpth[chHead[v]] > dpth[chHead[u]]) {
swap(u, v);
}
updateRange(ndToIdx[chHead[u]], ndToIdx[u], p, to_insert);
u = par[chHead[u]];
}
if (dpth[u] > dpth[v]) {
swap(u, v);
}
updateRange(ndToIdx[u], ndToIdx[v], p, to_insert);
}
} hld;
template <typename T>
class FenwickTree {
public:
vector<T> tree;
int n;
void init(int n) {
tree.assign(n + 2, 0);
this->n = n;
}
T mrg(T &x, T &y) { return x + y; }
void upd(int x, T v) {
for (; x <= n; x += (x) & (-x)) {
tree[x] = mrg(tree[x], v);
}
}
T getprefix(int x) {
if (x <= 0) return 0;
T rs = 0;
for (; x; x -= (x) & (-x)) {
rs = mrg(rs, tree[x]);
}
return rs;
}
T getrange(int l, int r) { return getprefix(r) - getprefix(l - 1); }
};
FenwickTree<ll> ft;
void solve_1() {
for (int i = 0; i < q; i++) {
cin >> t >> p >> u;
p--;
u--;
if (t == 1) {
v[p] = u;
} else {
if (v[0] == u) {
cout << 0 << endl;
} else {
cout << -1 << endl;
}
}
}
}
void solve_2() {
for (int i = 0; i < q; i++) {
cin >> t >> p >> u;
p--;
u--;
if (t == 1) {
v[p] = u;
} else {
if (hld.dist(v[0], u) + hld.dist(v[1], u) == hld.dist(v[0], v[1])) {
cout << hld.dist(v[p], u) << endl;
} else {
cout << -1 << endl;
}
}
}
}
void solve() {
for (int i = 0; i < q; i++) {
cin >> t >> p >> u;
--u, --p;
if (t == 1) {
int d = hld.dist(v[p], v[(p + 1) % k]);
ft.upd(p + 1, -d);
hld.update(v[p], v[(p + 1) % k], p, 0);
int b = (p + k - 1) % k;
d = hld.dist(v[p], v[b]);
hld.update(v[b], v[p], b, 0);
ft.upd(b+1, -d);
v[p] = u;
d = hld.dist(v[p], v[(p + 1) % k]);
ft.upd(p + 1, d);
hld.update(v[p], v[(p + 1) % k], p, 1);
d = hld.dist(v[p], v[b]);
ft.upd(b+1, d);
hld.update(v[b], v[p], b, 1);
} else {
int pos = hld.query(u, p);
if (pos == -1) {
cout << -1 << endl;
continue;
}
ll dist = hld.dist(v[pos], u);
if (pos >= p) {
dist += ft.getrange(p + 1, pos);
} else {
dist += ft.getrange(p + 1, k);
dist += ft.getprefix(pos);
}
cout << dist << endl;
}
}
}
void test_case() {
cin >> n >> k;
for (int i = 0; i < k; i++) {
cin >> v[i];
--v[i];
}
adj.init(n);
for (int i = 0; i < n - 1; i++) {
int u, v;
cin >> u >> v;
--u, --v;
adj.addBiEdge(u, v);
}
ft.init(k + 1);
hld.run(adj);
for (int i = 0; i < k; i++) {
hld.update(v[i], v[(i + 1) % k], i, 1);
ft.upd(i + 1, hld.dist(v[i], v[(i + 1) % k]));
}
cin >> q;
if (k == 1) {
solve_1();
} else if (k == 2) {
solve_2();
} else {
solve();
}
}
int main() {
// freopen("input.txt", "r", stdin);
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int T = 1;
while (T--) {
test_case();
}
return 0;
}