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Lazy
Problem: Given an array a1, a2, ..., an (1 <= n <= 1e6) and q queries, for each query has two types. 1 l r x: a[i] = min(a[i], x) (l <= i <= r). 2 i : print value in position i.
I dont know use lazy update to solve operator 1, help me pls (sorry i'm poor E).
