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CEOI 2016 Kangaroo Solution

Правка en2, от minimario, 2017-06-13 00:17:28

Hello :')

Recently I've solving this: link, and I've read solution here.

When the solution says, we can infer the following recurrences:

A[n][i][j] = D[n-1][i][j-1] + D[n-1][i+1][j-1] +…+ D[n-1][n-1][j-1]
D[n][i][j] = A[n-1][1][j-1] + A[n-1][2][j-1] +…+ A[n-1][i-1][j-1],

Is this only valid for i<j? Because the solution says, that when renumbering, we remove i and relabel everything greater than i. But if i>j, then the recurrence will not be D[n-1][smth][j-1], but rather D[n-1][smth][j].

But if both A and D are valid for only i<j, then do the formulas really work? Because in the sum for A[n][i][j], we will add some D[n-1][i'][j'] such that i'>j'. Then the recurrence wouldn't really work.

Can anyone provide some explanation or clarification on this?

Thanks,

-minimario

Теги ceoi, kangaroo, solution, sad!

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  Rev. Язык Кто Когда Δ Комментарий
en2 Английский minimario 2017-06-13 00:17:28 2 Tiny change: 'rrences:\n~~~~~\nA' -> 'rrences:\n\n~~~~~\nA'
en1 Английский minimario 2017-06-13 00:02:55 967 Initial revision (published)