All problem ideas belong to MikeMirzayanov. I just helped with testing, reviewing and tutorial writing.
Tutorial
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Solution
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> ans;
int power = 1;
while (n > 0) {
if (n % 10 > 0) {
ans.push_back((n % 10) * power);
}
n /= 10;
power *= 10;
}
cout << ans.size() << endl;
for (auto number : ans) cout << number << " ";
cout << endl;
}
}
Tutorial
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Solution
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, k;
cin >> n >> k;
int n1 = n - (k - 1);
if (n1 > 0 && n1 % 2 == 1) {
cout << "YES" << endl;
for (int i = 0; i < k - 1; ++i) cout << "1 ";
cout << n1 << endl;
continue;
}
int n2 = n - 2 * (k - 1);
if (n2 > 0 && n2 % 2 == 0) {
cout << "YES" << endl;
for (int i = 0; i < k - 1; ++i) cout << "2 ";
cout << n2 << endl;
continue;
}
cout << "NO" << endl;
}
}
1352C - K-th Not Divisible by n
Tutorial
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Solution
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, k;
cin >> n >> k;
int need = (k - 1) / (n - 1);
cout << k + need << endl;
}
}
1352D - Alice, Bob and Candies
Tutorial
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Solution in O(n)
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> a(n);
for (auto &it : a) cin >> it;
int l = 0, r = n - 1;
int suml = 0, sumr = 0;
int cnt = 0, ansl = 0, ansr = 0;
while (l <= r) {
if (cnt % 2 == 0) {
int nsuml = 0;
while (l <= r && nsuml <= sumr) {
nsuml += a[l++];
}
ansl += nsuml;
suml = nsuml;
} else {
int nsumr = 0;
while (l <= r && nsumr <= suml) {
nsumr += a[r--];
}
ansr += nsumr;
sumr = nsumr;
}
++cnt;
}
cout << cnt << " " << ansl << " " << ansr << endl;
}
}
Solution in O(n^2)
// Author: Ivan Kazmenko ([email protected])
import std.algorithm;
import std.conv;
import std.range;
import std.stdio;
import std.string;
void main ()
{
auto tests = readln.strip.to !(int);
foreach (test; 0..tests)
{
auto n = readln.strip.to !(int);
auto a = readln.splitter.map !(to !(int)).array;
int [2] total;
int prev = 0;
int moves = 0;
while (!a.empty)
{
moves += 1;
int cur = 0;
while (!a.empty && cur <= prev)
{
cur += a[0];
a = a[1..$];
}
total[moves % 2] += cur;
prev = cur;
reverse (a);
}
writeln (moves, " ", total[1], " ", total[0]);
}
}
Tutorial
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Solution
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> a(n);
vector<int> cnt(n + 1);
int ans = 0;
for (auto &it : a) {
cin >> it;
++cnt[it];
}
for (int l = 0; l < n; ++l) {
int sum = 0;
for (int r = l; r < n; ++r) {
sum += a[r];
if (l == r) continue;
if (sum <= n) {
ans += cnt[sum];
cnt[sum] = 0;
}
}
}
cout << ans << endl;
}
}
1352F - Binary String Reconstruction
Tutorial
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Solution
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n0, n1, n2;
cin >> n0 >> n1 >> n2;
if (n1 == 0) {
if (n0 != 0) {
cout << string(n0 + 1, '0') << endl;
} else {
cout << string(n2 + 1, '1') << endl;
}
continue;
}
string ans;
for (int i = 0; i < n1 + 1; ++i) {
if (i & 1) ans += "0";
else ans += "1";
}
ans.insert(1, string(n0, '0'));
ans.insert(0, string(n2, '1'));
cout << ans << endl;
}
}
Tutorial
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Solution
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
if (n < 4) {
cout << -1 << endl;
continue;
}
for (int i = n; i >= 1; --i) {
if (i & 1) cout << i << " ";
}
cout << 4 << " " << 2 << " ";
for (int i = 6; i <= n; i += 2) {
cout << i << " ";
}
cout << endl;
}
}