This Problem was given by DeadlyCritic as a challenge
Statement:
Given 1369D - TediousLee solve it for $$$10^{18}$$$ without using Matrix Exponentiation.
Solution:
In order to maximize the number of Claws, the basic idea is to keep track of $$$no. of nodes$$$ with no child at any $$$k^{th}$$$ $$$level$$$. So, max no of nodes that can be painted yellow for any $$$nth$$$ level is given by:
\begin{equation}\operatorname{sum}=4 *\left(\sum_{i=0}^{\left(\frac{n-2}{3}\right)} a_{((n-2) \% 3+3 i)}\right)\end{equation}
where, $$$a_{i}=$$$ no of nodes with no child at $$$i^{th}$$$ level
Now in order to get $$$a_{i}$$$ we use this recurrence: \begin{equation}f(x)=2 * f(x-2)+f(x-1)\end{equation}
Linear recurrence like this can be solve using characteristic equation, i will not get into details for the sake of keeping this blog short! Here is the equation:
\begin{equation}\begin{array}{c} f(x)-2 * f(x-2)-f(x-1)=0 \\ r^{n}-2 * r^{n-2}-r^{n-1}=0 \\ r^{n-2}\left(r^{2}-2-r\right)=0 \end{array}\end{equation}
From above, quadratic equation has two distinct solutions $$$r1 = 2$$$, $$$r2 = -1$$$
Now, \begin{equation}a_{n}=\alpha r_{1}^{n}+\beta r_{2}^{n}\end{equation} is the general term of the series we build from recurrence and, \begin{equation}\alpha=\frac{1}{3} \text { and } \beta=-\frac{1}{3}\end{equation} that can be easily found using initial conditions i.e. $$$a_{0} = 0$$$ & $$$a_{1} = 1$$$
Till now, \begin{equation}a_{n}=\frac{1}{3} *(2)^{n}-\frac{1}{3} *(-1)^{n}\end{equation} Finally, we have deduced the summation into a nice formula using geometric series \begin{equation}\operatorname{sum}=4 * \frac{1}{3} *\left(2^{(x \% 3)} *\left(\frac{8^{\left(\left|\frac{x}{3}\right|+1\right)}-1}{7}\right)-(-1)^{(x \% 3)} *\left(\frac{1-(-1)^{\left(\left|\frac{x}{3}\right|+1\right)}}{2}\right)\right)\end{equation}
where $$$x = n - 2$$$
Although, there can be many questions related to each step, but i'll leave that upon reader to think, all i wanted to is give the basic idea on how to solve this type of recurrence. Feel free to correct any errors. It was nice experience to write my first blog :)