Hi,
About three weeks ago, I asked a related question here. In that post, my program output to stdout, while it needs to be output into a file. A lot of people gives me suggestions to use freopen("Filename.in", "r", stdin); freopen("Filename.out", "w", stdout);
instead of ifstream
...
That's what I did and things have been ok for the past three weeks. However, when I tried to submit a solution using ```freopen", this happens:
I go check my solution and find no error that would cause "runtime error or memory limited exceeded". Therefore, I submitted it again, only replacing freopen
with ifstream
. Then, it gets accepted:
.
This might be a noobish question, but what causes this and how can I avoid that? Thank you!
P.S. This is the code:
#include<bits/stdc++.h>
#define ll long long
#define rep(i, m, n) for (int i = m; i <= n; i++)
#define per(i, m, n) for (int i = m; i >= n; i--)
#define FOR(i, m, n, k) for (int i = m; i <= n; i += k)
#define ROF(i, m, n, k) for (int i = m; i >= n; i -= k)
#define pb push_back
#define mp make_pair
#define pii pair<int, int>
#define all(v) v.begin(), v.end()
#define INF 0x3f3f3f3f
using namespace std;
const int maxn = 3e4 + 10;
struct edge {
int to, cost;
};
int N, T;
int a[105][105], dx[4] = {1, -1, 0, 0}, dy[4] = {0, 0, 1, -1};
int dis[maxn];
vector<edge> G[maxn];
int get(int x, int y, int t) {
return (x - 1) * N + y + t * N * N;
}
void dijkstra(int s) {
priority_queue<pii, vector<pii>, greater<pii> > q;
memset(dis, INF, sizeof(dis));
dis[s] = 0;
q.push(make_pair(0, s));
while (!q.empty()) {
pii p = q.top();
q.pop();
int u = p.second;
if (dis[u] < p.first) continue;
for (auto node : G[u]) {
int v = node.to;
if (dis[v] > dis[u] + node.cost) {
dis[v] = dis[u] + node.cost;
q.push(make_pair(dis[v], v));
}
}
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
// ifstream cin("visitfj.in");
// ofstream cout("visitfj.out");
freopen("visistfj.in", "r", stdin);
freopen("visistfj.out", "w", stdout);
cin >> N >> T;
rep(i, 1, N) rep(j, 1, N) cin >> a[i][j];
rep(i, 1, N) {
rep(j, 1, N) {
rep(k, 0, 3) {
int x = i + dx[k], y = j + dy[k];
if (x < 1 || x > N || y < 1 || y > N) continue;
rep(t, 0, 2) {
int nxt = (t + 1) % 3;
int cost = T + ((nxt == 0) ? a[x][y] : 0);
G[get(i, j, t)].pb((edge) {get(x, y, nxt), cost});
}
}
}
}
dijkstra(get(1, 1, 0));
int ans = INF;
rep(i, 0, 2) ans = min(dis[get(N, N, i)], ans);
cout << ans << "\n";
return 0;
}