| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | jiangly | 3977 |
| 2 | tourist | 3815 |
| 3 | jqdai0815 | 3682 |
| 4 | ksun48 | 3614 |
| 5 | orzdevinwang | 3526 |
| 6 | ecnerwala | 3514 |
| 7 | Benq | 3483 |
| 8 | hos.lyric | 3381 |
| 9 | gamegame | 3374 |
| 10 | heuristica | 3358 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | cry | 170 |
| 2 | -is-this-fft- | 162 |
| 2 | Um_nik | 162 |
| 4 | atcoder_official | 160 |
| 5 | djm03178 | 157 |
| 6 | Dominater069 | 156 |
| 7 | adamant | 154 |
| 8 | luogu_official | 152 |
| 8 | awoo | 152 |
| 10 | TheScrasse | 147 |
Hi codeforces community, I was solving 1820B - JoJo's Incredible Adventures and I got WA when I used s.length()*s.length(), but got AC when I used n*n (but n is the same as s.length()).
Is this supposed to happen?
299256114 is the AC code and 299255008 is the other one. Check the second "else if" statement at the end.
Hi, I came across many people talking about stress testing their code. What do they mean by that? Do they write a brute force and generate a large number of sample answers? or are there smarter ways to go about it?
