I have two integer b,n. I need to check if the number n is integer power of number b. For example: 100 is an integer power of 10. As 10^2 = 100. But 110 is not an integer power of 10. How to determine this in coding?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3839 |
3 | Radewoosh | 3646 |
4 | jqdai0815 | 3620 |
4 | Benq | 3620 |
6 | orzdevinwang | 3612 |
7 | Geothermal | 3569 |
7 | cnnfls_csy | 3569 |
9 | ecnerwala | 3494 |
10 | Um_nik | 3396 |
# | User | Contrib. |
---|---|---|
1 | Um_nik | 164 |
2 | maomao90 | 160 |
3 | -is-this-fft- | 159 |
4 | atcoder_official | 158 |
4 | cry | 158 |
4 | awoo | 158 |
7 | adamant | 155 |
8 | nor | 154 |
9 | TheScrasse | 153 |
10 | maroonrk | 152 |
I have two integer b,n. I need to check if the number n is integer power of number b. For example: 100 is an integer power of 10. As 10^2 = 100. But 110 is not an integer power of 10. How to determine this in coding?
Given an array of n-2 unique numbers in range 1 to n (inclusive). I want to find the missing two numbers in the array using xor. Please help me providing the idea. Thanks in advance.
Getting Runtime Error on test case 11 for 791B - Bear and Friendship Condition. Please help me.
Code: 25707815 [Python 3]
while (cin >> x) {
// code
}
I am a beginner in python. I've solved problems in some OJs with C++. Now i want to do it with Python 3. I started but i saw that my code wasn't not efficient. I got run time error or Time Limit. I faced problems taking input specially in UVa problems. Please help me.
Please help me to overcome time limit.
Problem Link: UVa 11340 Newspaper
My Code:
from sys import stdin,stdout
dd = dict()
tests = int(input().strip() )
for t in range(tests):
dd.clear()
sm = 0.0
m = int(input().strip())
for x in range(m):
ch,vl = input().strip().split()
dd[ch]=float(vl)
for x in range(int(input())):
line=input()
for letter in line:
if letter in dd:
sm += dd[letter]
print('%0.2f$' %(sm/100.0))
Name |
---|